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MAVERICK [17]
3 years ago
6

Suppose that 28% of domestic adoptions are transracial, and that 84% of international adoptions are

Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0

Answer: C

Not normal, because we expect fewer than 10 non-transracial international adoptions.

Step-by-step explanation: Khan Answer

1 - .84 = .16 So an estimated 16% of international adoptions will be non-transracial. In a sample size of 40 international adoptions only 6.4 will be non-transracial because .16 * 40 = 6.4 and 6.4 is less than 10, so we can not assume normality.

vlabodo [156]3 years ago
3 0

Answer:

Not normal, because we expect fewer than 101010 non-transracial international adoptions.

Step-by-step explanation:

Khan

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Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches
Mamont248 [21]

Answer:

6 in

Step-by-step explanation:

Let x = the side length of the original square.

They removed 3 in from each side of the original square, so the side lengths of the remaining square are x - 3 in.

The area of the smaller square is (x - 3)².

The area of the original square is x²

I assume the area of the smaller square is ¼ that of the original square. Then

1. Solve for x

\begin{array}{rcl}\frac{1}{4}x^{2} & = & (x - 3)^{2}\\x^{2} & = & 4(x - 3)^{2}\\& = & 4(x^{2} - 6x + 9)\\x^{2}& = & 4x^{2} - 24x + 36\\3x^{2} - 24x + 36 & = & 0\\x^{2} - 8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\x - 2 = 0& \qquad &x - 6 = 0\\x = 2& \qquad &x = 6\\\end{array}

2. Calculate the side length of the smaller square

(a) x = 2

Side length = x - 3 = 2 - 3 = -1 in.

IMPOSSIBLE. You can't have a negative side length.

(b) x = 6

Side length of smaller square = 6 - 3 = 3 in.

Side length of original square = x = 6 in

Check:

\begin{array}{rcl}\frac{1}{4}(6)^{2} & = & (6 - 3)^{2}\\\frac{1}{4}\times 36 & = & 3^{2}\\9 & = & 9\\\end{array}

OK.

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This data set is ages at first job. 14, 14, 16, 16, 17, 17, 18, 20, 21, 23 Construct a boxplot. Make sure to include labels.
aleksandr82 [10.1K]

Answer:

Please find attached the required box and whiskers plot

Step-by-step explanation:

The numbers are given in arranged order as follows;

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The five number summary are;

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The first quartile, Q₁, is the (n + 1)/4th term or the 2.75th term  = 14 + 0.75×(16 - 14) = 15.5

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