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3 years ago

12

During a sale, CDs that normally cost $6.98 each were priced at 2 for $12.50. Pete bought 4 CDs at the sale price. How much mone

y did he save by buying the 4 CDs on sale?

1 answer:

RSB [31]3 years ago

4 0

Answer:

2.92

Step-by-step explanation:

Normal price

4 * 6.98 =27.92

Sale price

2 for 12.50 means 4 at 2* 12.50

2*12.50 = 25

Subtract

27.92-25=2.92

He saved 2.92

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Evaluate b²c¹ for b=8 c=-4

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Answer:

The answer is -256.

Step-by-step explanation:

You have to substitute the value of b and c into the expression :

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Let b = 8,

Let c = -4,

${8}^{2} \times { - 4}^{1}$

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Can someone explain how to solve this I'm really confused <br><br> 1/2 to the power of 3

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Step-by-step explanation:

1/2 cubed is just 1/2*1/2*1/2 which is 1/8

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2 years ago

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A seamstress is paid $9.55 for every pair of pants made. how many pants would have to be made to receive $525.00 a week?

Svetlanka [38]

Let the number of pants have to be made be x.

So,

9.55 * x = 525.00

x = $\frac{525}{9.55}$ ≈ 54.97

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3 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

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Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

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so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

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so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

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###

Another way to do this:

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Then

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