Question

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Answer 1

Answer:

The correct answer is 2.33g of $H_{2}O$, A

Explanation:

We can use basic stoich to get this question.

To start, lets convert our grams to moles in order to use our equation. 5.38g of $O_{2} = (\frac{5.38}{2*15.999}) moles = 0.168136$ moles.

We then can use our molar ratio of 13:10. Simply divide by our molar ratio in order to go from moles of $O_{2}$ to moles of $H_{2}O$. This gets us 0.129335 moles of $H_{2}O$.

Now lets convert to grams of $H_{2}O$ by multiplying by the molar mass of $H_{2}O$. $.129335*(1.008*2+15.999) = 2.32997g$ of $H_{2}O$