Question

What mass of aluminum (in g) would be

Answer 1

Mass of Aluminum (in g) : 4.104

Further explanation

Reaction

2 Al(s) + 6 HCl(aq) → 2 AICI₃ (aq) + 3 H₂(g)

mol HCl :

$\tt 1.3\times 0.35=0.455$

mol Al :

$\tt \dfrac{2}{6}\times 0.455=0.152$

mass of Aluminum :

$\tt 0.152\times 27~g/mol=4.104~g$