Answer:
333.3mL
Explanation:
Using the formula as follows:
C1V1 = C2V2
Where;
C1 = initial concentration (M)
C2 = final concentration (M)
V1 = initial volume (mL)
V2 = final volume (mL)
According to the information provided in this question,
C1 = 4.00M
C2 = 1.50M
V1 = 125mL
V2 = ?
Using C1V1 = C2V2
4 × 125 = 1.5 × V2
500 = 1.5V2
V2 = 500/1.5
V2 = 333.3mL
Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.
The new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L. Details about volume of the gas can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the Boyle's law equation as follows:
P1V1 = P2V2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
1.53 × 5.6 × 10⁵ = 1.5 × 10⁵ × V2
8.568 × 10⁵ = 1.5 × 10⁵V2
V2 = 8.57 × 10⁵ ÷ 1.5 × 10⁵
V2 = 5.7L
Therefore, the new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L.
Learn more about volume at: brainly.com/question/12357202
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The size of the container.
Think about if you were stirring sugar into your cup of tea - the size of the cup doesn’t matter, but the other stuff does.
The question is incomplete, the complete question is;
The levels of organizations in multicellular organisms are shown below, but they are not in the correct order. Arrange the levels of organization in order from simplest to most complex. tissues organs whole organisms organ systems
Answer:
tissues --> organs --> organ system --> whole organisms
Explanation:
The levels of organizations in multicellular organisms refers to the increasing complexity of the components of the organism.
A tissue is an aggregation of cells hence it is the lowest level of organization here.
Organs are an aggregation of tissues, this is the next higher level of organization.
Organ systems are an aggregation of organs, this is the next higher level of organization.
Whole organisms are an aggregation of organ systems. This is the highest level of organization.
Answer:
The molar mass of the gas should be 43.0 g/mol.
Explanation:
1.Use the ideal gas law() & the formula for moles and molar mass().
2.Insert the equation into and re-arrange to solve for M(molar mass).
3.Insert values and use the gas constant R = since the volume is in liters and the pressure is in atmosphere units.
4. Your answer should be 42.99 g/mol or 43.0 g/mol.
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