Answer:
they must do a background check
Explanation:
they need to check the liscence and do a small interrigaition
First, write out a complete balanced reaction for the combustion of ethane, ethane + O2 -> CO2 + H20. Then, divide the grams of ethane by its Molar Mass and multiply by 32, the molar mass of O2.
Answer:then he has a lot of gas
Explanation
We balance the given reactions above by following the rules in balancing redox reactions in acidic or basic solutions. Balance the atoms aside from the O and H atoms. Then we balance the Os and Hs by adding H2O or H+. Finally, we balance the total charge of the reactant and product by adding e-. We do as follows:
<span>A) H2O2 + Fe 2+ ---> Fe 3+ + H2O (in the acidic solution)
</span><span> 2H+ + </span>H2O2 + Fe 2+ ---> Fe 3+ + 2H2O
e- + 2H+ + H2O2 + Fe 2+ ---> Fe 3+ + 2H2O
<span>
C) CN- + MnO4- ---> CNO- +MnO2 (in basic solution)
</span> CN- + MnO4- ---> CNO- +MnO2 + H2O
2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O
2OH- + 2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
2H2O + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
e- + H2O + CN- + MnO4- ---> CNO- +MnO2 + 2OH-
<span>
E) S2O2/3- + I2 ---> I- + S4O2/6- (in acidic solution)
2</span>S2O2/3- + I2 ---> 2I- + S4O2/6-
4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O
6e- + 4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O
Answer:
Final Volume = 0.31L
Explanation:
Initial volume V1 = 1L
Initial pressure P1 = 150kPa
Initial temperature, T1 = 25'C + 273 = 298K
Final Pressure P2 = 600kPa
Final Temperature T2 = 100'C + 273 = 373K
Final Volume V2 = ?
The combined gas law is given as;
P1V1 / T1 = V2P2 / T2
150 * 1 / 298 = V2 * 600 / 373
V2 = 55950 / 178800 = 0.31L
