Standard form is
ax+by=c
where a,b,c are integers
y+3=1/4x
timesboth sides by 4
4y+12=x
minus x both sides
-x+4y+12=0
minus 12 both sides
-x+4y=-12
(I like x to be positive so)
times both sides by -1
1x-4y=12
a=1
b=-4
c=12
Answer:
7
Step-by-step explanation:
We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.
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Let the thousands digit be 'd'. Then we want to find the integer solutions to ...
n -1000d = n/9
n -n/9 = 1000d . . . . . . add 1000d -n/9
8n = 9000d . . . . . . . . multiply by 9
n = 1125d . . . . . . . . . divide by 8
The values of d that will give a suitable 4-digit value of n are 1 through 7.
When d=8, n is 9000. Removing the 9 gives 0, not 1000.
When d=9, n is 10125, not a 4-digit number.
There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.
Answer:
x= 11.66667
Step-by-step explanation:
ok the six is repeating but, basically multiply 5 times 7, then divide that by 3
Answer:
4.1 sec
Step-by-step explanation:
h(t)=-3.2t^2+12.8t+1
h(t)=-3.2(t^2-4t)+1
h(t)=-3.2(t^2-4t+4-4)+1
h(t)=13.8-3.2(t-2)^2
For the ball to touch ground, h(t)=0.
13.8-3.2(t-2)^2=0
(t-2)=2.0766
t=4.07≈4.1 sec.
