First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Answer:
Step-by-step explanation:
10, 20, 30, 40
Answer:25
.036 is the answer. The first zero is in the tenths spot, the three is in the hundreths and the six is in the thousandths
Answer:
x = 3
Step-by-step explanation:
4(5x-3)=48 (Given)
4(5x)+4(-3)=48 (Distributive Property of Equality)
20x-12=48 (Simplify)
20x-12+12=48+12 (Addition Property of Equality)
20x=60 (Simplify)
(Division Property of Equality)
x = 3 (Simplify)
Using
sum = (n-2)180
= (15-2)180 = 13×180 = 2340°