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kow [346]
3 years ago
10

In a town there are 1,050 people who can vote. There were two candidates in the election for the town’s mayor. The results of th

e election are shown in the table.
What percentage of the 1,050 people actually did vote in the election?


A
20% of people who can vote

B
45% of people who can vote

C
55% of people who can vote

D
80% of people who can vote
Mathematics
2 answers:
kramer3 years ago
5 0

Answer: Not sure, but Ill go with C.

Step-by-step explanation:

bezimeni [28]3 years ago
3 0

Answer:

D-(80%)

Step-by-step explanation:

Since the total votes were 462+378=840 total votes, we divide that by the number of people in the town to get the percentage of people who voted. So 840/1050=80%

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Which expression is 5 times as large as the expression 345+23
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Answer:

1840

Step-by-step explanation:

345+23=368*5

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News article reports that "Americans have differing views on two potentially inconvenient and invasive practices that airports c
OverLord2011 [107]

Answer:

1) p1=0.83

2) p2=0.81

3) Option B

4) p=0.82

5) s=0.03

6) z=0.67

7) P=0.50

8) Do not reject H0

Step-by-step explanation:

1) The proportion of Republicans who think the full-body scans should be applied in airports is equal to the ratio between the republicans that think it should over the total Republicans in the poll:

p=X/n=258/311=0.83

2) The proportion of Democrats who think the full-body scans should be applied in airports is equal to:

p=X/n=294/363=0.81

3) As we want to know if there is a difference in the proportions calculated, not if one is higher or lower than the other, the correct option is B:

H_0:p_1-p_2=0\\\\H_a:p_1-p_2\neq0

4) The pooled estimate of a proportion is the average of both proportions:

\bar{p}=\frac{p_1+p_2}{2}= \frac{0.83+0.81}{2}=0.82

5) The standard error can be calculated as:

s=\sqrt{\frac{\bar{p}(1-\bar{p})}{n_1} +\frac{\bar{p}(1-\bar{p})}{n_2}} \\\\s=\sqrt{\frac{0.82*0.18}{311} +\frac{0.82*0.18}{363}} \\\\s=\sqrt{0.00047+0.00041} =\sqrt{0.00088}=0.03

6) The z-statistic can be calculated as:

z=\frac{p_1-p_2}{s}=\frac{0.83-0.81}{0.03}=\frac{0.02}{0.03}=0.67

7) The P-value for z=0.67 is P=0.50 (from the standard normal distribution table).

2P(Z>|z|)=0.50286

8) If the significance level is 0.01, the P-value is bigger than the significance level. The effect is not significanct. The null hypothesis is not rejected.

There is not enough evidence to say that both proportions are different.

A. Do not reject H0

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