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Paha777 [63]
2 years ago
13

If a number cube is rolled, how many times would we expect to get a number greater than 4 out of 240 trials?

Mathematics
2 answers:
Elanso [62]2 years ago
7 0
89 I think because I took the test
Rus_ich [418]2 years ago
6 0
240 divided by 4 is 60
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Which of the following scenarios represents<br>the smallest percent change?​
mestny [16]

Answer:

A baby that weighed 6 1/4 pounds at birth now weighs 8 pounds.

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLEIST
horsena [70]

Answer:

The picture shows the answer on the graph

Step-by-step explanation:

-2=-3/4×(x-6)

Distribute -3/4 through the parenthesis

-2= -3/4x+9/2

Multiply both sides of the equation by 4

-8=-3x+18

Move the variable to the left side and change its sign

3x-8=18

Move constant to the right side and change its sign

3x=18+8

Add the numbers

3x=26

Divide both sides of the equation by 3

x=26/3

Alternative Form- x=8 2/3 or x=8.6

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3 years ago
Write each number in SCENTIFic notation 64,000
adelina 88 [10]
Scientific notation means the numbers have to be between 1 and 10, so here is the answer as well as where to move the decimal

8 0
3 years ago
Daca a = 3-5 si b= 4:3*9:2
Thepotemich [5.8K]
A={2,3,5}
B={1,3,4}
A∩B={3}
R: a. {3}
5 0
2 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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