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3 years ago

9

Find the measures of the missing angles Help pleaseee

2 answers:

kondaur [170]3 years ago

6 0

Answer:

Nwm miałem to dawno powodzenia

kakasveta [241]3 years ago

6 0

100 is all the missing angels

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E. Original price:

Travka [436]

Answer:

79.20

Step-by-step explanation:

4 0

3 years ago

What is the missing number?<br><br> –3.4 + (–8 + 2) = [ _ + (–8)] + 2

Kisachek [45]

-3.4 + (-8 + 2) = ( _ + (-8) + 2)
-3.4 + (-6) = ( _ + (-8) + 2)
-9.4 = ( _ + (-8) + 2)
-9.4 = ( _ + -6)
Now remember whatever you do to one side you have to do to the other. :)
-9.4 - -6 = -6 - -6
= -3.4
You had to do one side of the equation before you could do the other side because you needed an answer to follow.

4 0

3 years ago

Read 2 more answers

(2x^2)^-4 how to solve this problem

Alinara [238K]

when you simplify this you get 1/16x^8

3 0

4 years ago

The following table displays the approximate number of centimeters, y, in x inches.

galben [10]

The answer it’s y=2.54x I just did the assignment

8 0

3 years ago

Read 2 more answers

In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from 0 to 10, where 0

uysha [10]

Answer:

a) A response of 8.9 represents the 92nd percentile.

b) A response of 6.6 represents the 62nd percentile.

c) A response of 4.4 represents the first quartile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5.9

Standard Deviation, σ = 2.2

We assume that the distribution of response is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) We have to find the value of x such that the probability is 0.92

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.92$

Calculation the value from standard normal z table, we have,

$P(z$

$\displaystyle\frac{x - 5.9}{2.2} = 1.405\\x = 8.991 \approx 8.9$

A response of 8.9 represents the 92nd percentile.

b) We have to find the value of x such that the probability is 0.62

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.62$

Calculation the value from standard normal z table, we have,

$P(z$

$\displaystyle\frac{x - 5.9}{2.2} = 0.305\\x = 6.571 \approx 6.6$

A response of 6.6 represents the 62nd percentile.

c) We have to find the value of x such that the probability is 0.25

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.25$

Calculation the value from standard normal z table, we have,

$P(z$

$\displaystyle\frac{x - 5.9}{2.2} = -0.674\\x = 4.4172 \approx 4.4$

A response of 4.4 represents the first quartile.

4 0

4 years ago