Find the total ways that people can be seated with no restrictions;
6! ways but you know that marcia and jan will not sit together.
Write out this, as: G, (M, J), B, P <-- M and J (Marcia and Jan are grouped together to find the ways they will be sat together, so we can subtract this away).
In this combination, considering M and J as one, you have 5! ways. Then you see that M and J can switch position, so there would be added 2! ways.
In total, possibility of J and M to sit together is 5!2!
6!-5!2!
=720-240
= 480 possible ways of seating the friends so that Jan and Marcia are not together.
Hope I helped :)
Answer:
1/2
Step-by-step explanation:
Answer:
Step-by-step explanation:
plug the numbers in and see if it is true
x=3, y=8
y=7x+8
8=7(3)+8
8=29
is not true, so it is not a solution. even if it might be a solution for the other equation, it is not true for this equation so it is not a solution for this system
how to find an equation: since y=7x+8 and y=x+1, then
7x+8=y, and y=x+1
7x+8=y=y=x+1
7x+8=x+1
6x+8=1
6x=-7
x=-7/6
y=x+1
y=-1/6
solution: (-1 1/6, -1/6)
Negative numbers.
Any number below zero is a negative number
Example :
10+34=
17
+34
_____
1
17
+34
_____
53
