The answer to the question is A
<span><span><span>2r - 9 > -6
</span><span>2r - 9 = -6
</span>2r = 3</span><span>
r = 3/2 = 1.5</span></span><span><span>
r > 1.5</span></span>
<span><span /></span><span><span>9x-5 < -41
</span><span>9x-5 = -41
9x = -36
x = -36/9 = -4
x < -4</span></span>
<span><span>3x + 13 > 7
3x + 13 = 7
3x = -6
x = -6/3 = -2
x > -2</span></span>
<span><span>4x + 3 > -17
4x + 3 = -17
4x = -20
x = -20/4 = -5
x > -5</span></span>
<span><span>7x - 4 < 10
7x - 4 = 10
7x = 14
x = 14/7 = 2
x < 2</span></span><span>
</span>
<span>A polynomial with the given zeros can be represented as
f(x) = (x-1)(x-2)(x+2)(x+3).
Note that if you set f(x) = 0, then 1,2,-2, and -3 certainly are the solutions. From here, we simply multiply/expand out the polynomial. We can do this in a variety of ways, one of which is taking the left two and right two products separately. We have
(x-1)(x-2) = x^2 - 3x + 2
and
(x+2)(x+3) = x^2 + 5x + 6.
This gives that
f(x) = (x^2 - 3x + 2) (x^2 + 5x + 6).
Expanding this expression out then gives us our answer as
f(x) = x^4 + 2x^3 - 7x^2 - 8x + 12
or answer choice B.</span>