Solve for <span>yy</span> in <span>2x+y=20<span>2x+y=20</span></span>How?
<span>y=20-2x<span>y=20−2x</span></span>
Substitute <span>y=20-2x<span>y=20−2x</span></span> into <span>-5y=-6x+12<span>−5y=−6x+12</span></span>How?
<span>-5(20-2x)=-6x+12<span>−5(20−2x)=−6x+12</span></span>
Solve for <span>xx</span> in <span>-5(20-2x)=-6x+12<span>−5(20−2x)=−6x+12</span></span>How?
<span>x=7<span>x=7</span></span>
Substitute <span>x=7<span>x=7</span></span> into <span>y=20-2x<span>y=20−2x</span></span>How?
<span>y=6<span>y=6</span></span>
Therefore,
<span>x=7<span>x=7</span></span>
<span>y=6<span>y=6</span></span>
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I must speak in your language
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Answer:
YES BUT NO BECAUSE WHERE DOES THE 11 COME FROM THATS WHAT I DONT GET? I DONT UNDERSTAND!!
Step-by-step explanation:
Answer:
pi + -pi = 0
Step-by-step explanation:
We need to have irrational numbers that we are adding and end up with a rational number. This means that it is not closed under addition
pi is an irrational number
0 is a rational number
pi + -pi = 0
irrational + irrational = rational
So... let's say, we have two numbers "a" and "b",
"a" is the smaller one, "b" is the larger one
so, their sum is 6
a + b = 6
3 times the smaller => 3 * a or 3a
now, two less than that
3a - 2
that equals the larger "b"
3a - 2 = b
solve for "a",
now, what's "b"? well, 3a - 2 = b :)