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2 years ago

Can someone help me on all three of these

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

4 0

5).85 6.)100 7.)40hope this helps this id what im positive of

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In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence

Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of z for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0

2 years ago

Help I’m stuck on this question I’ve been stuck on it for a while I can’t seem to figure it out please help for ten points

Naddika [18.5K]

Answer:

$\frac{1}{25}$

Step-by-step explanation:

I think what it is trying to say is that it wants the solution to multiplying all of those. The (...) simply means that it wants you to continue that pattern in what you are supposed to be multiplying, but stop at $\frac{24}{25}$ .

That would mean you are technically supposed to be multiplying:

$\frac{1}{2} \frac{2}{3} \frac{3}{4} \frac{4}{5} \frac{5}{6} \frac{6}{7} \frac{7}{8} \frac{8}{9} \frac{9}{10} \frac{10}{11} \frac{11}{12} \frac{12}{13} \frac{13}{14} \frac{14}{15} \frac{15}{16} \frac{16}{17} \frac{17}{18} \frac{18}{19} \frac{19}{20} \frac{20}{21} \frac{21}{22} \frac{22}{23} \frac{23}{24} \frac{24}{25}$

That is a lot and unfortunately, none of the individual fractions can be simplified within that. The final answer would be able to be simplified, though.

Multiplying the first four shown: $\frac{1}{2}\frac{2}{3} \frac{3}{4} \frac{4}{5}$ you end up with $\frac{24}{120}$ . Both the numerator (top) and the denominator (bottom) are divisible by 24. Dividing top and bottom would simplify this to $\frac{1}{5}$ .

Now, let's take the next four.

$\frac{5}{6}\frac{6}{7} \frac{7}{8} \frac{8}{9}$ allows you to end up with $\frac{1680}{3024}$ . Both the numerator (top) and the denominator (bottom) are divisible by 336. You are left with $\frac{5}{9}$ .

Now, let's take the next four.

$\frac{9}{10}\frac{10}{11} \frac{11}{12} \frac{12}{13}$ . Multiplying these gives you $\frac{11880}{17160}$ . Both the numerator (top) and the denominator (bottom) are divisible by 1320. You are left with $\frac{9}{13}$ .

Now, let's take the next four.

$\frac{13}{14}\frac{14}{15} \frac{15}{16} \frac{16}{17}$ . Multiplying these gives you $\frac{43680}{57120}$ . Both the numerator (top) and the denominator (bottom) are divisible by 3360. You are left with $\frac{13}{17}$ .

* Although I would continue to say let's take the next four, there appears to be a pattern in the simplification. The numerators we have gotten have all been four less than their denominators, and each numerator has been four more than the last. I cannot be certain, but we only have two sets of four left. If this pattern continues, the simplifications of each should be $\frac{17}{21}$ and $\frac{21}{25}$ . I will continue on for argument's sake, anyways.

The next four are $\frac{17}{18}\frac{18}{19} \frac{19}{20} \frac{20}{21}$ . Multiplying these, you are left with $\frac{116280}{143640}$ . Both the numerator (top) and the denominator (bottom) are divisible by 6840. We are left with $\frac{17}{21}$ . This is the exact guess I had made when following the pattern, and so the next one is most likely going to be the other guess as well.

Our final answer will be $\frac{1}{5}\frac{5}{9} \frac{9}{13} \frac{13}{17}\frac{17}{21} \frac{21}{25}$ all multiplied together. We end up with $\frac{208845}{5221125}$ . Both the numerator (top) and denominator (bottom) are divisible by 208845.

Simplified, your final answer is: $\frac{1}{25}$ .

* NOTE: that another way to solve this would just be to multiply all numbers from 1-24 together and then 2-25, but you would end up with a very large number that would be just as time consuming to simplify. To get the GCF fast, I used a GCF calculator.

6 0

2 years ago

Rajan bought 5 copies of a book to give as

solong [7]

Answer:

Step-by-step explanation:

the original price was the one she started at

8 0

3 years ago

Need help this please!

AnnZ [28]

Answer:

My earlier answer was deleted, so I'm reposting. The only thing I can think happened is that I included a link to a free bar chart program, which I used for the attached chart.

Step-by-step explanation:

Make your own chart or find an online bar chart utility. I was unable to properly label the title and axes on my chart, so modify these properties.

8 0

2 years ago

So here's the question

Lesechka [4]

Yes, is subtraction, to get their "difference".

first off, let's convert the mixed fractions, to "improper", and then subtract.

$\bf \stackrel{red~yarn}{9\frac{1}{5}}-\stackrel{blue~yarn}{3\frac{11}{25}}$

$\bf -------------------------------\\\\
\stackrel{mixed}{9\frac{1}{5}}\implies \cfrac{9\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{46}{5}}
\\\\\\
\stackrel{mixed}{3\frac{11}{25}}\implies \cfrac{3\cdot 25+11}{25}\implies \stackrel{improper}{\cfrac{86}{25}}\\\\
-------------------------------\\\\
\cfrac{46}{5}-\cfrac{86}{25}\impliedby \textit{our LCD is 25}\implies \cfrac{(5\cdot 46)~~-~~(1\cdot 86)}{25}
\\\\\\
\cfrac{230~-~86}{25}\implies \cfrac{144}{25}\implies 5\frac{19}{25}$

4 0

3 years ago