Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Answer:
Since both equations are equal to y, we can set them equal to each other.
y =-3x +8
y = -5x -2
-3x +8 = -5x -2
Solve for x.To do this, we need to get x by itself. First, move all the numbers to one side of the equation, and all the variables to the other.
-3x +8 = -5x -2
Add 5x to both sides
-3x+5x +8=-5x+5x -2
2x+8=-2
Subtract 8 from both sides
2x+8-8 = -2-8
2x=-10
Now, all the numbers are on one side, with the variables on the other. x is not by itself, it is being multiplied by 2. To undo this, divide both sides by 2
2x/2= -10/2
x= -5
Now, to find y, substitute -5 in for x in one of the equations.
y = -5x -2
y= -5(-5) -2
y=25-2
y=23
Put the solution into (x,y)
<u><em>The solution is (-5, 23)</em></u>