<span>2v^3 + 3v^2 + 4v + 6
= (</span><span>2v^3 + 3v^2) + (4v + 6)
= v^2 (2v + 3) + 2 (2v + 3)
= (v^2 + 2)(2v + 3)
hope it helps</span>
When dilation is about the origin, as it is here in every case, the image point coordinates are the original (pre-image) coordinates multiplied by the scale factor.
1. Multiply every coordinate value by 5:
... W' = (-5, 10), X' = (-15, -5), Y' = (25, -5), Z' = (15, 10)
2. Multiply every coordinate value by 1/3:
... A' = (-2, 5), B' = (0, 5/3), C' = (1, 10/3)
3. A' = (2, 8), B' = (6, 2), C' = (2, 2)
4. The image coordinates are 5 times the original coordinates, so ...
... the scale factor of the dilation is 5.
The rationalized form of 1+ √2/1-√2 is -2√2-3
Answer:
Step-by-step explanation:
To find the inverse of function y=f(x), swap variables and then solve for the original variable.
![y=(x-5)^3+1\\ \\ x=(y-5)^3+1\\ \\ x-1=(y-5)^3\\ \\ \sqrt[3]{x-1}=y-5\\ \\ y=\sqrt[3]{x-1}+5\\ \\ f^{-1}(x)=\sqrt[3]{x-1}+5](https://tex.z-dn.net/?f=y%3D%28x-5%29%5E3%2B1%5C%5C%20%5C%5C%20x%3D%28y-5%29%5E3%2B1%5C%5C%20%5C%5C%20x-1%3D%28y-5%29%5E3%5C%5C%20%5C%5C%20%5Csqrt%5B3%5D%7Bx-1%7D%3Dy-5%5C%5C%20%5C%5C%20y%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B5%5C%5C%20%5C%5C%20f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B5)
Answer:
I'm pretty sure the answer is E
