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DerKrebs [107]
3 years ago
8

Who can get this one?

Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0
Are you asking for the whole sheet? But the first would have both P and Q I think would be in in quadrant three. If you want more, just remember that the top right corner is 1, the top left is 2, bottom left is 3, and bottom right is 4.
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Graph the image of the figure after a dilation with a scale factor of 2 centered at (-7, - 2).
tigry1 [53]

Answer:

Sorry this is late!

Step-by-step explanation:

8 0
3 years ago
A train travels 16 miles in 20 minutes At this rate , how many minutes will it take to trace 12 miles?
VARVARA [1.3K]

Answer:

Write and solve an equation of ratios:

16 miles     20 min

-----------  = -----------

12 miles          x

Then 16x = 240, and x = 240/16 = 15.  

It will take 15 minutes to travel 12 miles.

3 0
3 years ago
Find the exact value of the remaining trigonometric functions given: Tan x = Undefined Sin x > 0
finlep [7]

Answer:

  • sin(x) = 1
  • cos(x) = 0
  • cot(x) = 0
  • csc(x) = 1
  • sec(x) = undefined

Step-by-step explanation:

The tangent function can be considered to be the ratio of the sine and cosine functions:

  tan(x) = sin(x)/cos(x)

It will be undefined where cos(x) = 0. The values of x where that occurs are odd multiples of π. The smallest such multiple is x=π/2. The value of the sine function there is positive: sin(π/2) = 1.

The corresponding trig function values are ...

  tan(x) = undefined (where sin(x) >0)

  sin(x) = 1

  cos(x) = 0

__

And the reciprocal function values at x=π/2 are ...

  cot(x) = 0 . . . . . . 1/tan(x)

  csc(x) = 1 . . . . . . .1/sin(x)

  sec(x) = undefined . . . . . 1/cos(x)

3 0
2 years ago
What is the equation in point slope form of a line that passes through the point (−8, 2) and has a slope of 12 ? Drag a number,
NemiM [27]
Point-slope form:

y − b = m(x − a<span>), where m is the slope and (a, b) is a point on the graph.

Here that would look like:

y - 2 = 12(x - (-8))
y - 2 = 12(x + 8)

The answer:
</span>y - 2 = 12(x + 8)

Hope this helps.
5 0
3 years ago
What is the image of point (4, 5) after a counterclockwise rotation of 270º about the origin?
andriy [413]
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.

Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.

A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>

Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
3 0
3 years ago
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