All categories

3 years ago

Who can get this one?

Mathematics

1 answer:

Ksivusya [100]3 years ago

3 0

Are you asking for the whole sheet? But the first would have both P and Q I think would be in in quadrant three. If you want more, just remember that the top right corner is 1, the top left is 2, bottom left is 3, and bottom right is 4.

You might be interested in

Someone help me with number 3

julia-pushkina [17]

Angle ABD = 40 Degrees. Angle DBC = 50 Degrees. Because we know that a right angle ( a boxed corner ) is 90 Degrees, you add up the X's and divide by 90 to find what X is. X in this case is 10. You then multiply using X ( 10 ). 4x10 is 40 and 5x10 is 50. Thus getting your angles.

7 0

4 years ago

Read 2 more answers

PLEASE HELP RIGHT AWAY, THANK U SO MUCH!! <3

vredina [299]

Answer:

1. Ans;

${a}^{7} \times {a}^{12} = {a}^{7 + 12} = {a}^{19}$

__o_o__

2. Ans;

$\frac{ {h}^{6} }{ {h}^{2} } = {h}^{4}$

__o_o__

3. Ans;

${e}^{6} \times {e}^{6} = {e}^{6 + 6} = {e}^{12}$

__o_o__

4.Ans;

$\frac{ {w}^{9} }{ {w} } = {w}^{8}$

__o_o__

5. Ans;

${g}^{2} \times {h}^{3} \times {g}^{2} \times h = {g}^{2 + 2} \times {h}^{3 + 1} = {g}^{4} {h}^{4}$

__o_o__

6.Ans;

$\frac{10 {a}^{12} }{ 6{a}^{3} } = \frac{5 {a}^{9} }{3}$

__o_o__

7.Ans;

$({m}^{4} )^{5} = {m}^{4 \times 5} = {m}^{20}$

__o_o__

8.Ans;

${(3 {a}^{2} })^{3} = ( {3})^{3} ( {a}^{2} ) ^{3} = 27 {a}^{6}$

__o_o__

9.Ans;

${( \frac{c}{k} })^{4} = \frac{ {c}^{4} }{ {k}^{4} }$

__o_o__

10.Ans;

${( \frac{8x}{9} })^{2} = \frac{( {8x})^{2} }{ ({9})^{2} } = \frac{64 {x}^{2} }{81}$

__o_o__

11.Ans;

$4 {c}^{2} \times {c}^{3} = 4 {c}^{2 + 3} = 4 {c}^{5}$

__o_o__

12.Ans;

${( - 9 {h}^{4} {k}^{6} })^{2} = {( - 9)}^{2} {( {h}^{4} })^{2} {( {k}^{6} })^{2} = 81 \: \: {h}^{8} {k}^{12}$

__o_o__

13.Ans;

$( { \frac{2d}{3e} })^{3} = \frac{ {(2d)}^{3} }{ ({3e)}^{3} } = \frac{8 {d}^{3} }{27 {e}^{3} }$

__o_o__

14. Ans;

${( \frac{4}{ {w}^{5} }) }^{3} = \frac{ ({4)}^{3} }{( {w}^{5} ) ^{3} } = \frac{64}{ {w}^{15} }$

_____o___o_____

$\frac{5 {v}^{4} \times 4 {v}^{5} }{2 {v}^{3} } = \frac{20 {v}^{4 + 5} }{2 {v}^{3} } = \frac{20 {v}^{9} }{2 {v}^{3} } = 10 {v}^{6}$

_o_o_

$( \frac{3 {f}^{4}h}{4 {h}^{9} } ) ^{3} = \frac{( {3})^{3} ( {f}^{4})^{3} ({h})^{3} }{ {(4)}^{3} ( {h}^{9})^{3} } \\ \\ \\ = \frac{27 {f}^{4 \times 3} {h}^{3} }{64 {h}^{9 \times 3} } = \frac{27 {f}^{12} {h}^{3} }{64 {h}^{27} } \\ \\ \\ = \frac{27 {f}^{12} }{64 {h}^{24} }$

I hope I helped you^_^

5 0

3 years ago

Simplify: 2y^2/ 4y^4 • 2y^3 A) xy^2/16 B) 1/y^6 C) y^3/6 D) 1/ 4y^5

Natali [406]

It is D. if you use a calculator it will tell you that. branliest?

3 0

3 years ago

Simplify: (-27)^2/3=

Jet001 [13]

Answer:

(-3^3 x 2/3)

(-3^2)

answer is 9

mark this as brainliest!!!

5 0

4 years ago

The weather during the day was 5°C. The temperature dropped 8° at night. What was the nighttime temperature?

blondinia [14]

Answer:

-3 degrees C

Step-by-step explanation:

you just subtract

8 0

3 years ago