$\bf f(x)=0.35x^2-2.1x+15.8\qquad 
\begin{cases}
x=\textit{year since 1995}\\
f(x)=\textit{population amount}
\end{cases}$

the equation is a quadratic one, and it has a positive coefficient on the leading term, meaning, is opening upwards, so it has a "burrow" for the vertex.

the minimum or lowest point for a quadratic opening upwards is, well, the vertex point :), the "x" value is the year, the "y" or f(x) value is the population, we're asked for the year, or the x-coordinate of the vertex

well $\bf \begin{array}{llll}
f(x)=&0.35x^2&-2.1x&+15.8\\
&\quad \uparrow &\quad \uparrow&\uparrow \\
&\quad a&\quad b &c
\end{array}
\\\\

\\\\
\qquad \textit{vertex of a parabola}\\ \quad \\
\qquad 

\left(\boxed{-\cfrac{{{ b}}}{2{{ a}}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

5 0

3 years ago

PLSS HELP<br><br> -21-9<br> ———-<br> -5

Simora [160]

Answer:

reduce the expression and if possible do that by cancelling the common factors :)

4 0

2 years ago

If f(x)=2x+1 and g(x)=1/2(x-1), what does f(g(-4)) equal

uranmaximum [27]

G(-4)

=1/2((-4)-1)

=1/2(-5)

=-2.5

------------------------------

f(g(-4))

=f(-2.5)

=2(-2.5)+1

=-5+1

=-4

5 0

2 years ago