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maw [93]
3 years ago
13

HELP MEEEEE!!!!plzzzz

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
Hmm i think either B or C. I think C more. ;-;
Simora [160]3 years ago
7 0

Answer:

c is the answer

Step-by-step explanation:

You might be interested in
Juanita begins to factor an expression as shown. x2+3x−18=(x+)(x−) What numbers should be placed in the boxes from left to right
stich3 [128]

Answer:

Option A is the correct answer.

Step-by-step explanation:

Here we need to factorize  x²+3x−18

The coefficient of x is 3 and the constant is -18

Which means

           The sum of factors is 3

           The product of factors is -18

The factors satisfying are  6 and -3

Here the factors are given in the type (x+)(x−)

     So the value after plus is 6 and value after - is 3

Option A is the correct answer.            

6 0
3 years ago
Read 2 more answers
Us the equation m= 15.75+ 32.d. Find M when d=20
EastWind [94]

Answer:

m= 655.75

Step-by-step explanation:

m=15.75+32d

m=15.75+32x20

m=15.75+640

m= 655.75

8 0
3 years ago
The ratio of mass to volume for a type of metal is 27 g to 10 cm³ a sample of the metal has a mass of 81 g what is the volume in
Kazeer [188]

Answer:

volume in cubic centimeters = 30 cm³

Step-by-step explanation:

Ratio of mass to volume = 27 g : 10 cm³

what is the volume in cubic centimeters of the sample of metal if mass = 81 g

Let

volume in cubic centimeters = v

Ratio of mass to volume = 81 g : v

Equate both ratios

27 g : 10 cm³ = 81 g : v

27/10 = 81/v

Cross product

27 * v = 10 * 81

27v = 810

v = 810/27

v = 30 cm³

volume in cubic centimeters = 30 cm³

5 0
3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 8​% will need repairs​
Sladkaya [172]

Answer:

Probability that a car need to be repaired​ once = 20% = 0.20

Probability that a car need to be repaired​ twice = 8% = 0.08

Probability that a car need to be repaired​ three or more = 2% = 0.02

a) If you own two​ cars what is the probability that  neither will need​ repair?

Probability that a car need to be repaired​ once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair=0.7 \times 0.7=0.49

​b) both will need​ repair?

Probability both will need​ repair = 0.3 \times 0.3=0.09

c)at least one car will need​ repair

Neither car will need repair=0.7 \times 0.7=0.49

Probability that at least one car will need​ repair= 1-0.49 = 0.51

6 0
3 years ago
What is the solution to this inequality?
kolbaska11 [484]

D.) x < -125

x<− 500/4

x<−125

6 0
3 years ago
Read 2 more answers
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