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3 years ago

12

A rectangular school flag has a base of 25 inches and a height of 32 inches. The flag is divided into 2 congruent triangles form

ed by 2 sides and a diagonal of the flag. What is the area of each triangle?

1 answer:

Musya8 [376]3 years ago

5 0

Answer:

both of the triangels have an area of 400

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3 years ago

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11) Find the doubling time for an amount invested at a growth rate 7% per year compounded continuously.

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3 years ago

Please help and fast

kirza4 [7]

A the slope of the line is 1

to calculate the slope m , use the ' gradient formula '

m = ( y₂ - y₁ ) /( x₂ - x₁ )

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3 years ago

Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

garri49 [273]

Answer:

BE = 294.23 ft

PE = 259.62 ft

Step-by-step explanation:

Quadrilateral CPRG is a parallelogram.

CP || GR

In triangles BCG and BPE

$\angle BCG \cong \angle BPE (Alternate \: \angle 's) \\\angle GBC \cong \angle EBP (Vertical \: \angle 's) \\\therefore \triangle BCG \sim \triangle BPE (AA \: postulate) \\\\\therefore \frac{BE}{BG} =\frac{PE}{GC} =\frac{BP}{BC}...(csst)\\\\\therefore \frac{BE}{425} =\frac{PE}{375} =\frac{225}{325}\\\\\therefore \frac{BE}{425} =\frac{PE}{375} =\frac{9}{13}\\\\\therefore \frac{BE}{425} =\frac{9}{13}\\\\BE =\frac{9\times 425}{13}\\\\BE =\frac{3,825}{13}\\\\BE = 294.23\: ft \\\\\&\\\frac{PE}{375} =\frac{9}{13}\\\\PE =\frac{9\times 325}{13}\\\\PE =\frac{3,375}{13}\\\\PE = 259.615385 \\\\PE = 259.62 \: ft\\\\$

7 0

3 years ago