Question

Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

Answer 1

Answer:

BE = 294.23 ft

PE = 259.62 ft

Step-by-step explanation:

Quadrilateral CPRG is a parallelogram.

CP || GR

In triangles BCG and BPE

$\angle BCG \cong \angle BPE (Alternate \: \angle 's) \\\angle GBC \cong \angle EBP (Vertical \: \angle 's) \\\therefore \triangle BCG \sim \triangle BPE (AA \: postulate) \\\\\therefore \frac{BE}{BG} =\frac{PE}{GC} =\frac{BP}{BC}...(csst)\\\\\therefore \frac{BE}{425} =\frac{PE}{375} =\frac{225}{325}\\\\\therefore \frac{BE}{425} =\frac{PE}{375} =\frac{9}{13}\\\\\therefore \frac{BE}{425} =\frac{9}{13}\\\\BE =\frac{9\times 425}{13}\\\\BE =\frac{3,825}{13}\\\\BE = 294.23\: ft \\\\\&\\\frac{PE}{375} =\frac{9}{13}\\\\PE =\frac{9\times 325}{13}\\\\PE =\frac{3,375}{13}\\\\PE = 259.615385 \\\\PE = 259.62 \: ft$