C.) x(t)=59cos(45)t and y(t)=-16^2 +59sin(45)t + 4
0=0
it is n the range of 0≤x≤4
so
do x+3
0+3=3
it is 3
<span>k^2+11k has 11 as the coefficient of the first power of the variable (k).
To complete the square:
Take HALF of this coefficient. In other words, take HALF of 11, obtaining 11/2.
Square this (11/2): (121/4)
Add this 121/4 to </span><span>k^2+11k
Result: </span><span>k^2+11k + 121/4
This is a perfect square: </span>k^2+11k + 121/4 = (k + 11/2)^2
Answer: The number to be added to k^2 + 11k to make it a perfect square is (121/4).
Start at negative 5 go up three to the left one and to do the other sode of thw graph, do the opposite
first of all, lets set up the equation
3x + 2y = 31
9x + 8y = 103
+--------------------
now make them equal
12x + 8y = 124
9x + 8y = 103
+----------------------
x=7
y=5
