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serg [7]
3 years ago
11

What must be true of a linear system for it to have a unique​ solution? select all that apply.

Mathematics
1 answer:
Natalija [7]3 years ago
3 0
There are NO choices.
I know for TWO linear equations to have a unique solution they CANNOT be parallel.

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What is the result when the number 20 is decreased by 75%?\
Viefleur [7K]

Answer:

5

Step-by-step explanation:

If 20 is <em>decreased </em>by 75%, you would have to do 20×0.25 because 1.00-0.75= 0.25. Therefore, the answer to your question would be 5.

Hope this was helpful!!!

8 0
3 years ago
This figure is made up of a rectangle and parallelogram.
ivann1987 [24]

The area of the figure is 40 units. (rounded off from 39.998 units)

Step-by-step explanation:

1. Area of the figure = Area of Rectangle + Area of Parallelogram.

2. Naming points:

Let the rectangle consist of points A(-6,-1), B(-5,-5), C(3,-3) and D(2,1).

Let the parallelogram consist of points C(3,-3), D(2,1), E(2,7) and F(3,3).

3. Each coordinate has a point on the x-axis and a point on the y-axis. We shall refer to these points as x', x'' ,x''' and so on corresponding to the x-axis values of A, B, C and so on in that order till F. For the y-axis points, we will name them in the series of y', y'', y''' and so on.

In simple words, in A(-6,1), x' = -6; y' = -1

4. Formula for finding area:

Area of a rectangle = length (l) × width (w)

Area of a parallelogram = base (b) x height (h)

5. Finding area of the rectangle:

l = AD = \sqrt{[x'''' - x']^{2} - [y'''' - y']^{2}}

, i.e. AD = \sqrt{[2 - (-6)]^{2} - [1 - (-1)]^{2}}

, i.e. AD = √68 = 8.246 (rounded to 3 decimals) = l

Now, w = AB = \sqrt{[x'' - x']^{2} - [y'' - y']^{2}}

, i.e. AB = \sqrt{[(-5) - (-6)]^{2} - [(-5) - (-1)]^{2}}

, i.e. AB = √17 = 4.123 (rounded to 3 decimals) = w

Area of rectangle = l x w = 8.246 x 4.123 = 33.998 units.

6. Finding area of the parallelogram:

b = DE = 6 units (we can observe this from the graph, i.e. points from 1 to 7 on the y axis)

h = Height is the line drawn perpendicular to the base from point F, which as we can see is 1 unit long.

Hence, Area of parallelogram = b x h = 6 x 1 = 6 units.

7. Now, adding both, we can arrive at the final answer.

Area of the figure = Area of rectangle + Area of parallelogram,

i.e. 33.998 units + 6 units = 39.998 units. (can be rounded off to 40 units)

4 0
2 years ago
Any help? I'm struggling.
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

a=-7

r=21/-7=-3

a_{15}=a r^{n-1}=-7(-3)^{15-1}=-7(-3)^{14}=-33480783

4 0
2 years ago
ABCD is a parallelogram. E is the point where the diagonals AC and BD meet. Prove that triangle ABE is congruent to triangle CDE
Darina [25.2K]
ABCD is a parallelogram                  Given
AE=CE, BE=DE                                <span>The diagonals of a parallelogram are                                                                     bisect each other
</span>∠AEB=∠CED                                    Vertical angles are congruent
ΔABE is congruent to ΔCDE            SAS theorem<span>
</span>
5 0
3 years ago
Read 2 more answers
Find the values of k so that each remainder is three. <br> 10. (x^2+ 5x + 7) = (x + k)
Goryan [66]

Answer:

k=1\text{ or } k=4

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a <em>binomial</em> in the form (x - a), then our remainder will be P(a).

We are dividing:

(x^2+5x+7)\div(x+k)

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

(-k)^2+5(-k)+7=3

Simplify:

k^2-5k+7=3

Solve for <em>k</em>. Subtract 3 from both sides:

k^2-5k+4=0

Factor:

(k-1)(k-4)=0

Zero Product Property:

k-1=0\text{ or } k-4=0

Solve:

k=1\text{ or } k=4

So, either of the two expressions:

(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)

Will yield 3 as the remainder.

5 0
3 years ago
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