Answer correctly please !!!! Will mark Brianliest !!!!!!!!!!!!!!
2 answers:
Answer:
Side Length AB = 22
Side Length CB = 35.21
Side Length = 41.52
Angle A = 58°
Angle B = 90°
Angle C = 32°
Step-by-step explanation:
- Side Length CB;
Tan(32) = 22 / CB
Tan(32) * CB = 22
CB = 22 / Tan(32)
CB = 35.21
- Side Length AC; (Now that we know the Length of AB and BC)
22² + 35.21² = AC²
484 + 1239.74 = AC²
1723.74 = AC²
= AC
41.52 = AC
- Angle A (Since we know Angle B and Angle C)
Angle A + Angle B + Angle C = 180°
Angle A + 32° + 90° = 180
Angle A + 122 = 180
Angle A = 180 - 122
Angle A = 58°
Hope this helps!
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Step-by-step explanation:
The word "LAMEFIREALARM" word consists of
2L , 2M, 2E , 2R , 3A , F and I
no of words with the above letters such that M's are not together
=Total No of words- M's are together
Total no of words
When M's are together . considering 2 M's as one
therefore there are
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(b)No of ways such that M's are separated by at least 2 letters
at least 2 letter means 2 letter, 3 letter ......11 letters
So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other
No of ways in which there is 1 letter between 2 M's
This can be done by considering 11 cases
In first case Place first M in Starting Position and 2 M on third place
Second case place First M in 2 nd Position and second M on 4 th place
Similarly For 11th case
Place first M in 11th place and second M on 13th place
Total ways
So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is