Y= ∛(-x) - 3
for x = -8 → y = ∛-(-8) - 3 ↔ y = 2-3 ↔y = -1
for x= 8 → y= ∛(-8) - 3 ↔ y = -2 -3 ↔ y = -5
Then - 5≤ y≤ - 1
hence the range of y is {y|-5≤y≤-1}
That answer was (B)................
Answer: y = (x + 5)² + 8
<u>Step-by-step explanation:</u>
y = x²
left 5 units: y = (x + 5)²
up 8 units: y = (x + 5)² + 8
Lets write the problem info into an equation and solve step by step:
7(1/3 + 4/5)
the minimum common multiple of 3 and 5 is 15, so we multiply and divide the fractions by a proper number to convert them to be divided by 15 so is easier to add them:
<span>(1/3)(5/5) = (1*5)/(3*5) = 5/15
(4/5)(3/3) = (4*3)/(5*3) = 12/15
</span>so we substitute in the original equation:
7(1/3 + 4/5<span>)
</span>= 7(5/15 + 12/15<span>)
= 7(17/15)
= (7*17)/15
= 119/15</span>
Let
x---------> the larger number
y---------> the smaller number
we know that
x+y=148------> equation 1
x=3y-2------> equation 2
substitute 2 in 1
[3y-2]+y=148--------> 4y=150---------> y=150/4------> y=37.5
x=3y-2----> x=3*37.5-2-----> x=110.5
the answer is
the larger number is 110.5
the smaller number is 37.5
