For this case , the parent function is given by [tex f (x) =x^2
[\tex]
We apply the following transformations
Vertical translations :
Suppose that k > 0
To graph y=f(x)+k, move the graph of k units upwards
For k=9
We have
[tex]h(x)=x^2+9
[\tex]
Horizontal translation
Suppose that h>0
To graph y=f(x-h) , move the graph of h units to the right
For h=4 we have :
[tex ] g (x) =(x-4) ^ 2+9
[\tex]
Answer :
The function g(x) is given by
G(x) =(x-4)2 +9
The answer is at 7:12 a.m, did you get that?
Answer:
66
Step-by-step explanation:
(5 - 3)⁴ - 2(7) + 8²
PEMDAS
Parentheses first
(2)⁴ - 2(7) + 8²
Exponents
16 - 2(7) + 64
Multiply and divide from left to right
16 -14 +64
Add and subtract from left to right
2+64
66
The unit vector is given by the following formula:
a '= (a) / (lal)
Where,
a: vector a
lal: Vector module a
We are looking for the module:
lal = root ((- 15) ^ 2 + (8) ^ 2)
lal = 17
Same direction:
a = -15i + 8j
The unit vector is:
a '= (1/17) * (- 15i + 8j)
Opposite direction:
a = 15i - 8j
The unit vector is:
a '= (1/17) * (15i - 8j)
Answer:
a unit vector that has the same direction as the vector a is:
a '= (1/17) * (- 15i + 8j)
a unit vector that has the opposite direction of the vector a is:
a '= (1/17) * (15i - 8j)
