Answer:
Square root of 27/4 rounded to the nearest tenth = 6.8
Step-by-step explanation:
Answer:
v = ± sqrt(6/5)
Step-by-step explanation:
v^2+2=8-4v^2
Add 4v^2 to each side
v^2+ 4v^2+2=8-4v^2+ 4v^2
5v^2 +2 = 8
Subtract 2 from each side
5v^2 +2-2 = 8-2
5 v^2 = 6
Divide each side by 5
5v^2 /5 = 6/5
v^2 = 6/5
Take the square root of each side
sqrt(v^2) = ± sqrt(6/5)
v = ± sqrt(6/5)
(x^2 - 1)(x^6 + x^4 + x^2) =
x^2(x^6 + x^4 + x^2) - 1(x^6 + x^4 + x^2) =
x^8 + x^6 + x^4 - x^6 - x^4 - x^2 =
x^8 - x^2 <==
the fraction is 60/100 or in sipulist form 6/10 as a desimel of tenths it would equel .6
What do you mean instead it is true 4x6 is 24 but if you 1/4 x 6 is 6/4 or 1 1/2
