Answer:
Perimeter = 12+5+12+5 = 34 units
Area = 12*5 = 
Step-by-step explanation:
You could use the cubes and a hot clue gun to make a model version of it.
The coefficients of x and y in the first equation are 3 and -4, respectively.
The coefficients of x and y in the second equation are 1 and 6, respectively.
The coefficient matrix lists these coefficients in order on successive rows, so it will be ...
![\left[\begin{array}{cc}3&-4\\1&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%26-4%5C%5C1%266%5Cend%7Barray%7D%5Cright%5D)
Answer:
The cost would be same after 3 months.
Step-by-step explanation:
Given that:
Charges of first company;
Sign up fee = $76
Per month charges = $40
Let,
x be the number of months
y be the total cost.
y = 40x + 76 Eqn 1
Charges of second company;
Sign up fee = $136
Per month charges = $20
y = 20x + 136 Eqn 2
For same cost,
Eqn 1 = Eqn 2
40x + 76 = 20x + 136
40x-20x = 136 - 76
20x = 60
Dividing both sides by 20
Hence,
The cost would be same after 3 months.
We have five value in the data-set
The third value will be 10 since we want the median to be 10
We want the mean to be 14
To find the mean of a data set, we divide the sum of the values by the number of values
Mean = Sum of values ÷ Number of values
14 = Sum of values ÷ 5
Sum of values = 14 × 5
Sum of values = 70
So we need 5 values that add up to 70, one of the value is 10, which is the median. We would want two values that are smaller than 10 and two values more than 10.
These four value must add up to 70 - 10 = 60
From here we can do trial and error:
Choose any two values less than 10, say 9 and 8
We now have in total 8 + 9 + 10 = 27
We have 70 - 27 = 43 left to find
Choose any two values that are bigger than 10 that add up to 43, for example, 20 and 23
Now we have our 5 values;
8 9 10 20 23
Do the checking bit:
We can see from the set, the median is 10
Mean = [8+9+10+20+23] ÷ 5 = 70 ÷ 5 = 14
We can have values other than 8, 9, 20 and 23 as long as two values smaller than 10 and two values more than 10. All five values must add up to 70.
