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Phantasy [73]
3 years ago
8

One cell phone company charges a $76 sign-up fee and $40 per month. Another cell phone company charges $136 sign-up fee and $20

per month. Write and solve an equation to determine after how many months the cost is the same
Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0

Answer:

The cost would be same after 3 months.

Step-by-step explanation:

Given that:

Charges of first company;

Sign up fee = $76

Per month charges = $40

Let,

x be the number of months

y be the total cost.

y = 40x + 76      Eqn 1

Charges of second company;

Sign up fee = $136

Per month charges = $20

y = 20x + 136     Eqn 2

For same cost,

Eqn 1 = Eqn 2

40x + 76 = 20x + 136

40x-20x = 136 - 76

20x = 60

Dividing both sides by 20

\frac{20x}{20}=\frac{60}{20}\\x=3

Hence,

The cost would be same after 3 months.

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Help this is due in 2 minutes
IgorLugansk [536]

Answer:

6% growth

Step-by-step explanation:

The equation =

A = 2300(1.06)⁷

What does 0.06 represent in the equation?

The formula for Exponential growth =

y = a (1 +r)^t

Where

y = Size after time t

a = Initial size

r = Growth rate in Percentage

t = Time t

Equating both Equations together

y = a (1 +r)^t = A = 2300(1.06)⁷

1 + r = 1.06

r = 1.06 - 1

r = 0.06

Converting to percent

r = 0.06 × 100

r = 6% growth rate

8 0
3 years ago
Can anyone answer this please? I need help
BARSIC [14]

Answer:

84 cm squared, 30 cm squared, 18 cm squared

Step-by-step explanation:

Formula for triangle area= 1/2 Base * Height

Area for triangle ABD= 1/2 (12cm)*(14cm)

                                   =84 cm squared

Area for triangle BC(orange triangle)= 1/2 (6cm)*(10cm)

                                   =30 cm squared

BC=  half of BD

Area for triangle CD(Green  triangle)= 1/2 (6cm)*(4cm)

                                   =12 cm squared

4 0
3 years ago
Read 2 more answers
Find a decomposition of a=⟨−5,−1,1⟩ into a vector c parallel to b=⟨−6,0,6⟩ and a vector d perpendicular to b such that c+d=a.
dezoksy [38]

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

In this question, we need to determine all projections of a vector with respect to another vector. In this case, the projection of vector A <em>parallel</em> to vector B is defined by this formula:

\vec a_{\parallel , \vec b} = \frac{\vec a \,\bullet\,\vec b}{\|\vec b\|^{2}}\cdot \vec b (1)

Where \|\vec b\| is the norm of vector B.

And the projection of vector A <em>perpendicular</em> to vector B is:

\vec a_{\perp, \vec b} = \vec a - \vec a_{\parallel, \vec b} (2)

If we know that a = \langle -5, -1, 1 \rangle and \vec b = \langle -6, 0, 6 \rangle, then the projections are now calculated:

\vec a_{\parallel, \vec b} = \frac{(-5)\cdot (-6)+(-1)\cdot (0)+(1)\cdot (6)}{(-6)^{2}+0^{2}+6^{2}} \cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \frac{1}{2}\cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \langle -3, 0, 3\rangle

\vec a_{\perp, \vec b} = \langle -5, -1, 1 \rangle - \langle -3, 0, 3 \rangle

\vec a_{\perp, \vec b} = \langle -2, -1, -2\rangle

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

We kindly invite to check this question on projection of vectors: brainly.com/question/24160729

7 0
3 years ago
If one inch represents 3 units, what dimensions would you use to draw a rectangular field that is 20 units by 14 units?​
mezya [45]

Answer:

Step-by-step explanation:

If 1 inch = 3 units,

Therefore 1 unit = ⅓ inches, so to answer your question we have to

Multiply it by 20, to have :

20 units = 20× ⅓ = 20÷3

20 units = 6.66

Therefore we can use the same principle in that of 14 units.

14 units = (14 × ⅓) inches

14 units = 4.66 inches

PLEASE GIVE BRAINLIEST.

5 0
3 years ago
What is a unit rate????????????????????????????????????????????
Ksivusya [100]
The rate of a unit per one. So for example 40miles/1hour. Hope it helped. :)
5 0
4 years ago
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