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Phantasy [73]
3 years ago
8

One cell phone company charges a $76 sign-up fee and $40 per month. Another cell phone company charges $136 sign-up fee and $20

per month. Write and solve an equation to determine after how many months the cost is the same
Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0

Answer:

The cost would be same after 3 months.

Step-by-step explanation:

Given that:

Charges of first company;

Sign up fee = $76

Per month charges = $40

Let,

x be the number of months

y be the total cost.

y = 40x + 76      Eqn 1

Charges of second company;

Sign up fee = $136

Per month charges = $20

y = 20x + 136     Eqn 2

For same cost,

Eqn 1 = Eqn 2

40x + 76 = 20x + 136

40x-20x = 136 - 76

20x = 60

Dividing both sides by 20

\frac{20x}{20}=\frac{60}{20}\\x=3

Hence,

The cost would be same after 3 months.

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Answer:

f(x)=8x^2+73x-70

Step-by-step explanation:

We are given

zeros as -10 and 7/8

now, we can set up function as

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now, we are given that

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now, we can plug it

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