Question

PLEASE HELP!! ASAP WILL GIVE BRAILIST (please explain how you got there or show a picture of work)

Answer 1

Answer:

See Explanation

Explanation:

a) The word equation is;

silver chlorate + sodium phosphate ------> silver phosphate + sodium chlorate

b) The balanced reaction equation of the reaction is;

3AgClO3(aq) + Na3PO4(aq) ------->Ag3PO4(s) + 3NaClO3(aq)

c) amount of silver chlorate reacted = 287 g/191.319 g/mol = 1.5 moles

3 moles of silver chlorate yields 1 mole of silver phosphate

1.5 moles of silver chlorate yields 1.5 * 1/3 = 0.5 moles of silver phosphate

Amount of sodium phosphate reacted = 52.8 g/163.94 g/mol = 0.3 moles

1 mole of sodium phosphate yields 1 mole of silver phosphate

0.3 moles of sodium phosphate yields 0.3 moles of silver phosphate.

Hence the maximum number of grams mass of silver phosphate produced = 0.3 moles * 418.58 g/mol = 125.6 g

d) The excess reactant is silver chlorate while the limiting reactant is sodium phosphate

e) 3 moles of silver chlorate  reacts with 1 mole of sodium phosphate

  x moles of silver chlorate reacts with 0.3 moles of sodium phosphate

x = 3 * 0.3 = 0.9 moles of silver chlorate reacted

Mass of 0.9 moles of silver chlorate = 0.9 moles * 191.319 g/mol  = 172 g of silver chlorate

Hence mass of silver chlorate left over =  287 g - 172 g = 115 g