Answer:
See Explanation
Explanation:
a) The word equation is;
silver chlorate + sodium phosphate ------> silver phosphate + sodium chlorate
b) The balanced reaction equation of the reaction is;
3AgClO3(aq) + Na3PO4(aq) ------->Ag3PO4(s) + 3NaClO3(aq)
c) amount of silver chlorate reacted = 287 g/191.319 g/mol = 1.5 moles
3 moles of silver chlorate yields 1 mole of silver phosphate
1.5 moles of silver chlorate yields 1.5 * 1/3 = 0.5 moles of silver phosphate
Amount of sodium phosphate reacted = 52.8 g/163.94 g/mol = 0.3 moles
1 mole of sodium phosphate yields 1 mole of silver phosphate
0.3 moles of sodium phosphate yields 0.3 moles of silver phosphate.
Hence the maximum number of grams mass of silver phosphate produced = 0.3 moles * 418.58 g/mol = 125.6 g
d) The excess reactant is silver chlorate while the limiting reactant is sodium phosphate
e) 3 moles of silver chlorate reacts with 1 mole of sodium phosphate
x moles of silver chlorate reacts with 0.3 moles of sodium phosphate
x = 3 * 0.3 = 0.9 moles of silver chlorate reacted
Mass of 0.9 moles of silver chlorate = 0.9 moles * 191.319 g/mol = 172 g of silver chlorate
Hence mass of silver chlorate left over = 287 g - 172 g = 115 g
