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weqwewe [10]
3 years ago
15

Will heating generally increase or decrease the amount of solid solute that will dissolve in the solution?

Chemistry
1 answer:
mario62 [17]3 years ago
3 0
The answer is “B” because I just answered it
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Based on appearances, which group of animals likely has the greatest genetic diversity?
svp [43]
I think that the answer would be birds because they are very different depending on species
5 0
3 years ago
Read 2 more answers
21. How many moles of NaNO, are used if 8.36 g of O, is produced?
iris [78.8K]

Answer:

Much like a dozen is equal to 12 (this could be doughnuts, eggs, people, etc.), one mole is equal to 6.022 x 1023 atoms, molecules, electronsExplanation:

4 0
3 years ago
Suppose a liquid level from 5.5 to 8.6 m is linearly converted to pneumatic pressure from 3 to 15 psi. What pressure will result
wlad13 [49]

Answer:

a) P = 9.58 psi for  h=7.2 m

b) P=4.7 psi for h=5.94 m

Explanation:

Since the pressure Pon a static liquid level h is

P= p₀ + ρ*g*h

where p₀= initial pressure , ρ=density , g = gravity

then he variation of the liquid level Δh will produce a variation of pressure of

ΔP= ρ*g*Δh → ΔP/Δh =  ρ*g = ( 15 psi - 3 psi) /( 8.6 m - 5.5 m)  = 12/3.1 psi/m

if the liquid level is converted linearly

P = P₁ + ΔP/Δh*(h -h₁)

therefore choosing  P₁ = 3 psi and h₁= 5.5 m , for h=7.2 m

P = 3 psi  + 12/3.1 psi/m *(7.2 m -5.5 m) = 9.58 psi

then P = 9.58 psi for  h=7.2 m

for P=4.7 psi

4.7 psi = 3 psi  + 12/3.1 psi/m *(h -5.5 m)

h = (4.7 psi - 3 psi)/ (12/3.1 psi/m) + 5.5 m = 5.94 m

then P=4.7 psi for h=5.94 m

5 0
4 years ago
A container of oxygen gas is at STP. If this sample is put into an oven at 280 C, what would its pressure be, in atmospheres?
Leni [432]

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial pressure (P1) = 1atm

Initial temperature (T1) = 0°C = 0°C + 273 = 273K

Final temperature (T2) = 280°C = 280°C + 273 = 553K

Final pressure (P2) =...?

Step 2:

Determination of the new pressure of the gas.

Since the volume of the gas is constant, the following equation:

P1/T1 = P2/T2

will be used to obtain the pressure. This is illustrated below:

P1/T1 = P2/T2

1/273 = P2 / 553

Cross multiply

273x P2 = 553

Divide both side by 273

P2 = 553/273

P2 = 2.03atm

Therefore, the new pressure of the gas will be 2.03atm

3 0
3 years ago
Read 2 more answers
Fluorine gas a 300 K occupies a volume of 500 mL. To what temperature should it be lowered to bring the volume to 300 mL?
snow_tiger [21]
180 K

V1/T1 = V2/T2
V1 = 500 mL
T1 = 300 K
V2 = 300 mL

Solve the equation for T2 —> T2 = V2T1/V1

T2 = (300 mL)(300 K) / (500 mL) = 180 K
6 0
3 years ago
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