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qwelly [4]
3 years ago
10

0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g = ? How many digits to the right of the decimal point should be used to report the resu

lt?
Chemistry
2 answers:
cestrela7 [59]3 years ago
5 0

Answer:

You should use 5 digits to the right of the decimal point.

Explanation:

To be precise in the mathematical operation you have to conserve all significant digits .

Replace the scientific notation for its equivalent in decimal notation:

2.70 x 10-4 g = 0.00027  g

4.21 x 10-3  g = 0.00421  g

Then, compute the addition and subtraction :

0.01360  g

+  

0.00027  g

-  

0.00421  g

-------------

0.00966 g = 9.66 x 10-3 g

That means you should use 5 digits to the right of the decimal point, which are the biggest amount of digits necessary to represent  2 of the numbers involved in the mathematical operation.

ki77a [65]3 years ago
4 0

Consider the following equation:0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g  = ? How many digits to the right of the decimal point should be used to report the result? =2, Choose the correct answer=9.66 × 10^-3 g, Which metric unit would be the best choice to report the result?=mg

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Calculate the number of water (H2O) molecules produced from the decomposition of 75.50 grams of Iron (III) hydroxide (Fe(OH)3).
Phantasy [73]

Answer: 6.38\times 10^{23} molecules of water are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe(OH)_3=\frac{75.50g}{106.8g/mol}=0.707moles

The balanced chemical reaction is:

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O  

According to stoichiometry :

2 moles of Fe_2O_3 produce = 3 moles of H_2O

Thus 0.707 moles of Fe_2O_3 will produce=\frac{3}{2}\times 0.707=1.06moles  of H_2O  

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus 1.06 moles of H_2O contains = \frac{6.023\times 10^{23}}{1}\times 1.06=6.38\times 10^{23} molecules

5 0
3 years ago
A titanium cube contains 3.10•10^23 atoms. The density of a titanium is 4.50g/cm^3. What is the edge length of the cube?
Lerok [7]

Answer:

1.76cm

Explanation:

We'll begin by calculating the mass of titanium that contain 3.10x10²³ atoms. This can be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10²³ atoms. This implies that 1 mole of titanium also contains 6.02x10²³ atoms.

1 mole of titanium = 48g

Now, if 48g of titanium contains 6.02x10²³ atoms,

Then Xg of titanium will contain 3.10x10²³ atoms i.e

Xg of titanium = (48x3.10x10²³)/6.02x10²³

Xg of titanium = 24.72g

Next, we shall determine the volume of the titanium. This is illustrated below:

Density of titanium = 4.50g/cm³

Mass of titanium = 24.72g

Volume of titanium =..?

Density = Mass /volume

Volume = Mass /Density

Volume of titanium = 24.72g/4.50g/cm³

Volume of titanium = 5.49cm³

Finally we shall determine the edge length of the titanium cube as follow:

Volume = L³

5.49cm³ = L³

Take the cube root of both side

L = 3√(5.49cm³)

L = 1.76cm

Therefore, the edge length is 1.76cm

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