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qwelly [4]
3 years ago
10

0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g = ? How many digits to the right of the decimal point should be used to report the resu

lt?
Chemistry
2 answers:
cestrela7 [59]3 years ago
5 0

Answer:

You should use 5 digits to the right of the decimal point.

Explanation:

To be precise in the mathematical operation you have to conserve all significant digits .

Replace the scientific notation for its equivalent in decimal notation:

2.70 x 10-4 g = 0.00027  g

4.21 x 10-3  g = 0.00421  g

Then, compute the addition and subtraction :

0.01360  g

+  

0.00027  g

-  

0.00421  g

-------------

0.00966 g = 9.66 x 10-3 g

That means you should use 5 digits to the right of the decimal point, which are the biggest amount of digits necessary to represent  2 of the numbers involved in the mathematical operation.

ki77a [65]3 years ago
4 0

Consider the following equation:0.0136 g + 2.70 × 10-4 g - 4.21 × 10-3 g  = ? How many digits to the right of the decimal point should be used to report the result? =2, Choose the correct answer=9.66 × 10^-3 g, Which metric unit would be the best choice to report the result?=mg

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I need help with this question
Maru [420]

Aluminum sulfide : Al₂S₃

ratio cation : anion = 2 : 3

<h3>Further explanation</h3>

Given

Compound of Aluminium

Required

cations anions ratio

Solution

Salt can be formed from cations and anions which have their respective charges.

In the chemical compound formula these charges are crossed with each other

For aluminum it has a +3 charge

1. Aluminum carbide : Al₄C₃

ratio cation : anion = 4 : 3

2. Aluminum chloride : AlCl₃

ratio cation : anion = 1 : 3

3. Aluminum sulfide : Al₂S₃

ratio cation : anion = 2 : 3

4. Aluminum nitride : AlN

ratio cation : anion = 1 : 1

3 0
3 years ago
What is 2.75 mol of O2
ANTONII [103]

Answer:

2,75 mol of O2 it's 88 g of O2.

Explanation:

The weight of the diatomic molecule O2 is 32 g/mol. So considering that, you should multiply 2,75 mol · 32 = 88g :)

3 0
3 years ago
The enthalpy of formation of xef2(g) is –108 kj mol–1 and the bond dissociation enthalpy of the f–f bond is 155 kj mol–1 . what
S_A_V [24]
Xe +f2 →Xef2
ΔXe = ΣB.P reactants - Σ B.d products
-108k.s/ mol = B. D f₂ - 2 B.D xe-f
-108 k.s/mol =155 k.s/mol - 2B.Dxe-f
263kJ/mol/2 = B. D xe-f
B.D xef = 131.5 kJ/mol
132 kJ/mol
4 0
3 years ago
Read 2 more answers
A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

                           d = \frac{g}{mL} \\\\ V= \frac{g}{d}  = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L

Now, find moles of CH_{3} OH are needed using the molarity equation:

                           M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH  = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

5 0
3 years ago
Identify the two main materials that can be found in the inner and outer core layers of the earth.
Mrrafil [7]
A. Iron D. Nickel hope this helps you!
6 0
3 years ago
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