First, write the dissociation equation for PbCO3 which is PbCO3 = Pb^(2+) + CO3^(2-). Then, write the Ksp equation which is Ksp = [Pb^(2+)][CO3^(2-)]. The equation suggests that there is 1:1 molar ratio between the Pb^(2+), CO3^(2-) and the dissolved PbCO3. Thus in equation form, we can represent them as x. The Ksp equation is then: 1.5*10^-15 = x^2. The molar solubility of PbCO3, x, is then equal to 3.87*10^-8 moles per liter.
Answer:
Shift it toward the reactants.
Explanation:
Answer:
ΔU = -6.2 × 10⁴ J
Explanation:
The system absorbs 965 J of heat, that is, q = 965 J.
The work (w) can be calculated using the following expression.
w = -P . ΔV
where,
P is the external pressure
ΔV is the change in the volume
w = - (1.90 × 10⁵ N/m²) × (0.51 m³ - 0.18 m³) = -6.3 × 10⁴ J
The change in the internal energy (ΔU) is:
ΔU = q + w = 965 J + (-6.3 × 10⁴ J) = -6.2 × 10⁴ J
Answer:
7.54%
Explanation:
A hydrate is a salt that has molecules of water incorporated into the crystals. It is represented by the molecular formula of the salt followed by how many molecules of water it has: XY.nH₂O.
So, the mass of water in the sample will be the difference between the hydrate and the salt without water:
mass of water = 1.034 - 0.956 = 0.078 g
The mass percentage is the mass of water divided by the total mass, and then multiplied by 100%:
(0.078/1.034)x100%
7.54%
Answer:
Sodium reacts with the oxygen in air. It reacts vigorously with oxygen and the moisture that is already present in the air and thus catches fire.