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Gelneren [198K]
3 years ago
5

The ratio of boys to girls in a class is 7:5. There are 36 students in the class. How many

Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0

Answer:

There would be 15 girls and 21 boys

Mama L [17]3 years ago
3 0

15 girls and 21 boys are in the class

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Right or wrong ????
tangare [24]

Answer:

c   1/2

Step-by-step explanation:

You are incorrect.

We are going from ABCDEFGH to A'B'C'D'E'F'G'H'. We are going from the large octagon to the small octagon. The scale factor of a dilation is the number you multiply the original lengths to get the lengths of the dilation.

scale~factor = \dfrac{length~of~dimension~in~dilated~image}{length~of~corresponding~dimension~in~original~figure}

Look at point (6, 0) which becomes (3, 0) in the dilation.

The distance from the origin to (6, 0) is 6 units.

The distance from the origin to (3, 0) is 3 units.

scale factor = dilated/original = 3/6 = 1/2

The scale factor of the dilation is 1/2.

Also look at segment AB whose length is 4. The length of segment A'B' is 2.

scale factor = dilated/original = 2/4 = 1/2

Answer: 1/2

4 0
3 years ago
A bag contains white marbles and red marbles, 90 in total. The number of white marbles is 6 less than 5 times the number of red
Gelneren [198K]

Answer:

W = 72

Step by step explanation:

White = W

Red = R

W + R = 90

Write an equation

W = 5R - 6

Substitute

5R - 6 = 90

Add 6 to both sides of the equation

5R = 90

Simplify

90 ÷ 5 = 18

R = 18

90 - 18 = W

W = 72

Hope this was useful to you!

8 0
3 years ago
How many different ways can you decompose 6/8 fraction into sum of fractions with the same denominator?
dem82 [27]
Well there's only one i can think of and that's 3/4
3 0
3 years ago
Read 2 more answers
How many candy bars must be sold to earn a profit of $600
Juliette [100K]
Well, it depends how much is each candy bar?
8 0
2 years ago
Read 2 more answers
Please help! I really need it!
amm1812

Answer:

1.  x > 4

2.  m < 2

3.  x > 2

4.  x < -6

Step-by-step explanation:

These 4 inequalities will be solved the same way we solve equations. We take variables to one side and numbers to another and use algebra to solve. Each of them are solved shown below:

1.

4+6x

so x is greater than 4, we can write (variable first):

x > 4

2.

m+16>8m+2\\16-2>8m-m\\14>7m\\\frac{14}{7}>m\\2>m

so m is less than 2, we can write:

m < 2

3.

5x-1>13-2x\\5x+2x>13+1\\7x>14\\x>\frac{14}{7}\\x>2

so x is greater than 2, we can write:

x > 2

4.

-3x-2>-x+10\\-2-10>-x+3x\\-12>2x\\\frac{-12}{2}>x\\-6>x

so x is less than -6, we can write:

x < -6

8 0
3 years ago
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