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3 years ago

The ratio of boys to girls in a class is 7:5. There are 36 students in the class. How many

Mathematics

2 answers:

Whitepunk [10]3 years ago

7 0

Answer:

There would be 15 girls and 21 boys

Mama L [17]3 years ago

3 0

15 girls and 21 boys are in the class

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The coordinates of quadrilateral ABCD are A(-1,-5), B(8,2), C(11,13), and D(2,6). Using coordinate geometry, prove that quadrila

Sliva [168]

Answer:

The quadrilateral ABCD is a rhombus.

Step-by-step explanation:

A rhombus is a quadrilateral having equal sides.

If ABCD is a rhombus then,

AB = BC = CD = DA

It is provided that the coordinates of the rhombus ABCD are:

A = (-1, -5)

B = (8, 2)

C = (11, 13)

D = (2, 6)

Use the distance formula to compute the lengths of AB, BC, CD and DA.

The distance formula is:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Compute the length of AB:

$AB=\sqrt{(8-(-1))^{2}+(2-(-5))^{2}}=\sqrt{130}=11.4$

Compute the length of BC:

$BC=\sqrt{(11-8)^{2}+(13-2)^{2}}=\sqrt{130}=11.4$

Compute the length of CD:

$CD=\sqrt{(2-11)^{2}+(6-13)^{2}}=\sqrt{130}=11.4$

Compute the length of DA:

$DA=\sqrt{(2-(-1))^{2}+(6-(-5))^{2}}=\sqrt{130}=11.4$

Thus, the lengths AB, BC, CD and DA are equal, i.e. all sides are of length 11.4.

Hence proved that the quadrilateral ABCD is a rhombus.

7 0

3 years ago

A manufacturer produces 25-pound lifting weights. The lowest actual weight is 24 pounds, and the highest is 26 pounds. Each weig

stealth61 [152]

Answer:

0.45

Step-by-step explanation:

For a uniform distribution,

$f(x) = \frac{1}{b - a} \\$

where a is the minimum and b the maximum\\

cumulatively, $F(x) = \frac{x - a}{b -a}$

$F(x >= 24.9) = \frac{24.9 - 24}{26 - 24} = \frac{0.9}{2} = 0.45$

6 0

3 years ago

I need help very fast plz someone help

jarptica [38.1K]

Answer:

4-9=-5

Step-by-step explanation:

do the work you get that

6 0

3 years ago

Read 2 more answers

Express 1 m as a percentage of 56 mm

hichkok12 [17]

Answer:

Step-by-step explanation:

use your head

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2 years ago

Verify the identity. Show your work. 1 + sec^2xsin^2x = sec^2x

allsm [11]

$\bf \textit{Pythagorean Identities}
\\\\
1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\
1+sec^2(x)sin^2(x)=sec^2(x)
\\\\\\
1+\cfrac{1}{cos^2(x)}\cdot sin^2(x)\implies 1+\cfrac{sin^2(x)}{cos^2(x)}\\\\\\ 1+tan^2(x)\implies sec^2(x)$

4 0

3 years ago