<em>Complete Question:</em>
<em>A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled, what is the probability of rolling a number greater than 10?</em>
Answer:

Step-by-step explanation:
Given
Number of Sides = 12
Required
Probability of obtaining a side greater than 10
We start by listing out the sample space;


Next, we list out digits greater than 10; Represent this with T


Probability of T is calculated as follows;


Divide the numerator and denominator by 2

<em>Hence, the required probability is </em>
<em />
Answer:
1.81,2.54,3.77
Total
8.12
Step-by-step explanation:
To find the tax, multiply the original amount by the tax rate
tax
25 * 7.25%
25 *.0725
Rounding to the nearest cent
1.81
35 * 7.25%
35 *.0725
Rounding to the nearest cent
2.54
52 * 7.25%
52 *.0725
Rounding to the nearest cent
3.77
Total for all three
1.81+2.54+3.77=8.12
The answer is 28 tenths.
Because, 66 subtracted by 38 equals....28
0.09 is 10 times as much as 0.009, since it is one decimal place behind 0.09!
Hope I was able to help, if you need any more help, please let me know.
Answer:
92.99
Step-by-step explanation: