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pentagon [3]
3 years ago
13

If an arrow is shot upward on Mars with a speed of 68 m/s, its height in meters t seconds later is given by

Mathematics
1 answer:
Talja [164]3 years ago
6 0

Answer:

(a) dy/dt = 68 - 3.72t

(b) 64.28m/s

Step-by-step explanation:

Given y = 68t - 1.86t²

Average Speed is rate of chance of distance with respect to time. Written as dy/dt

To obtain dy/dt, we differentiate y with respect to t, doing that, we have

dy/dt = 68 - 2(1.86)t

= 68 - 3.72t

(a) dy/dt = 68 - 3.72t

(b) To estimate the speed when t = 1, we substitute t = 1 in dy/dt .

dy/dt at t = 1 is

68 - 3.72(1)

= 68 - 3.72

= 64.28

The speed at t = 1 is 64.28m/s

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56.55 inches

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Answer:

n(U)=200

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3 years ago
Read 2 more answers
Bob decides he wants to make guitars and sell them online. He makes and sells Gibson Explorer’s and Gibson Flying V’s. He can ma
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e + v > or = 30.

80e + 5v =m.
 
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1600 + 50 = 1650.
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7 0
3 years ago
Please help asap !!!!!! what vaule of x makes the equation true 3(x-4)=15
DaniilM [7]

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3 years ago
In the figure, angle D measures 45° and angle E measures 87°. What is the measurement of angle H? 42°
Vinvika [58]
<span>The complete question is shown in the attached image

<u><em>Answer:</em></u>
measure angle H = 42</span>°<span>

<u><em>Explanation:</em></u>
<u>There is a theorem that states that:</u>
"In a triangle, the measure of the exterior angle is equal to the sum of the measures of the two non-adjacent angles to the exterior angle"

<u>In the given, we have:</u>
angle E is an exterior angle to triangle DFH
The two non-adjacent angles to angle E are angles D and H

<u>Based on the above rule:</u>
measure angle E = measure angle D + measure angle H

<u>We are given that:</u>
angle E = 87</span>°<span>
angle D = 45</span>°<span>

<u>Substitute with the givens in the above rule and solve for the measure of angle H as follows:</u>
angle E = angle D + angle H
87</span>°<span> = 45</span>°<span> + measure angle H
measure angle H = 87</span>°<span> - 45</span>°<span>
measure angle H = 42</span>°<span>

Hope this helps :)</span>

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