Answer:
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Step-by-step explanation:
We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 35
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of ![1 - \frac{1 - 0.9}{2} = 0.975([tex]t_{975}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B1%20-%200.9%7D%7B2%7D%20%3D%200.975%28%5Btex%5Dt_%7B975%7D)
). So we have T = 2.0322
The margin of error is:
M = T*s = 2.0322*30 = 60.97
The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Answer:
12.5 hours
Step-by-step explanation:
10 / 4 = 2.5
2.5 * 5 = 12.5
Answer:
<h3>20</h3>
Step-by-step explanation:
According to Triangle P R Q, if angles R P Q and P Q R are congruent, this means that two of the sides of the triangle a re also congruent (Isosceles triangle).
We can say then that length of side PR is equal to that of RQ i.e PR = RQ
Given
PR = 5n
RQ = 32+n
Required
Length of PR
Since the two sides are equal i.e PR = RQ
5n = 32+n
5n - n = 32
4n = 32
n = 32/8
n = 4
Get PR;
Since PR = 5n
PR = 5(4)
PR = 20
Hence the length of PR is 20.
Answer:
Width: x + 3
(Length, width):
(5,4) (6,5) (7,6)
Step-by-step explanation:
x² + 7x + 12
x² + 4x + 3x + 12
x(x + 4) + 3(x + 4)
(x + 4)(x + 3)
Longer one is the length,
With is (x + 3)
x = 1,
5 × 4
x = 2,
6 × 5
x = 3,
7 × 6
Answer:
see explanation
Step-by-step explanation:
Euler's formula states that the sum of the number of faces (F) and the number of vertices (V) of a polyhedra is equivalent to two more than the number of its edges (E) , that is
F + V = E + 2
