3 years ago

Which of the following is not true about arid deserts?

Physics

1 answer:

andrezito [222]3 years ago

3 0

Answer:

The answer is actually b

Explanation:

The rain falls mostly as snow during the winter.

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Radioactive iodine (radioiodine) is given to patients with some forms of thyroid cancer in order to destroy the cancer cells. 13

Eva8 [605]

Answer:

I think is D

Explanation:

Please mark me as brainliest

4 0

3 years ago

A 240 g toy car is placed on a narrow 60-cm-diameter track with wheel grooves that keep the car going in a circle. The 1.0 kg tr

lesya [120]

Answer:

The track's angular velocity is W2 = 4.15 in rpm

Explanation:

Momentum angular can be find

I = m*r^2

P = I*W

So to use the conservation

P1 + P2 = 0

I1*W1 + I2*W2 = 0

Solve to w2 to find the angular velocity

0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2

W2 = 0.435 rad/s

W2 = 4.15 rpm

8 0

3 years ago

True or False? Gases such as water vapor condense when they are *heated*.

scoundrel [369]

That statement is <em>false</em>.

"Condense" is what a gas does when it turns into liquid, and that's something that happens when the gas is cooled, not heated.

4 0

3 years ago

A car traveling at 31 m/s starts to decelerate steadily. It comes to a complete stop in 7 seconds. What is its acceleration

N76 [4]

Vf=V1+at
0=31+a(7)
-31/7=a
a=-4.43m/s^2

Hope this helps.

8 0

3 years ago

To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeof

BlackZzzverrR [31]

<h2>Answer: 26,8 s</h2>

Explanation:

If we are talking about an acceleration at a constant rate , we are dealing with constant acceleration, hence we can use the following equations:

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (1)

$V_{f}=V_{o}+at$ (2)

Where:

$V_{f}$ is the final velocity of the plane (the takeoff velocity in this case)

$V_{o}=0$ is the initial velocity of the plane (we know it is zero because it starts from rest)

$a=5m/s^{2}$ is the constant acceleration of the plane to reach the takeoff velocity

$d=1800m$ is the distance of the runway

$t$ is the time

Knowing this, let's begin with (1):

${V_{f}}^{2}=0+2(5m/s^{2})(1800m)$ (3)

${V_{f}}^{2}=18000m^{2}/s^{2}$ (4)

$V_{f}=134.164 m/s$ (5)

Substituting (5) in (2):

$134.164 m/s=0+(5m/s^{2})t$ (6)

Finding $t$ :

$t=26.8 s$ This is the time needed to take off

6 0

3 years ago