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svp [43]
3 years ago
13

Seasonal changes bring about scenes like this one. Plant cells respond to changes in _________________ and as a result, photosyn

thesis slows and leaves change color.
Physics
2 answers:
NikAS [45]3 years ago
6 0

The answer is; light intensity & temp change

As winter approaches, the chlorophyll molecules reduce (by being broken down) and this is why leaves begin to turn orange as there are more red pigments (Xanthophyll) than the green pigment. This is because as winter approached, the light intensity decreases and it gets colder. Therefore, the plants begin to prepare for the harsh incoming weather. Most deciduous trees even begins to shed their leaves.


jekas [21]3 years ago
4 0
Light intensity & temp change 
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What does the Bohr Model show us?
aivan3 [116]

Answer:

2

Explanation:

5 0
3 years ago
A mass m at the end of a spring vibrates with a frequency
Wittaler [7]

Answer:

m = 0.59 kg.

Explanation:

First, we need to find the relation between the frequency and mass on a spring.

The Hooke's law states that

F = -kx

And Newton's Second Law also states that

F = ma = m\frac{d^2x}{dt^2}

Combining two equations yields

a = -\frac{k}{m}x

The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.

\omega = \sqrt{\frac{k}{m}}

And given that ω = 2πf

the relation between frequency and mass becomes

f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}.

Let's apply this to the variables in the question.

0.88 = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\\0.60 = \frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}\\\frac{0.88}{0.60} = \frac{\frac{1}{2\pi}\sqrt{\frac{k}{m}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}}\\1.4667 = \frac{\sqrt{m+0.68}}{\sqrt{m}}\\2.15m = m + 0.68\\1.15m = 0.68\\m = 0.59~kg

6 0
3 years ago
Mike stands on a scale in an elevator. If the elevator is accelerating upwards with 4.9 m/s2, the scale reading is ____ times Mi
Bas_tet [7]

Answer:

F - M a      force exerted by scales on student

M a = M (9.8 + 4.9) m/s^2      upwards chosen as positive

a = 1.5 g        net acceleration of student  due to force of scales

W =M g       weight of student   (actual weight)

Wapp = M 1.5 * g      apparent weight (on scales) of student

7 0
3 years ago
This armed
Tanya [424]

Answer:

5.59 m/s2

Explanation:

F = 1900 N

m = 340 kg

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Therefore, a = 1900/340 = 5.59

3 0
3 years ago
Red laser light passes through a single slit to form a diffraction pattern. If the width of the slit is increased by a factor of
SCORPION-xisa [38]

If the width of the slit is increased by a factor of two , then the central maxima will get decreased by half.

since , width of the central maxima is inversely proportional to the width of the slit . Which implies if width of the slit get increased then width of the central maxima will get decreased and vice versa.

central maxima = (2 * wavelength * D) / width of the slit

                          = (2 * lambda * D) / d

if initially width of the slit = d

then, after increasing it by a factor of two it become =  2d

central maxima  =  (2 * lambda * D) / 2d

                           = (lambda * D) / d

If the width of the slit is increased by a factor of two , then the central maxima will get decreased by half.

Learn more about central maxima :

brainly.com/question/14279157?referrer=searchResults

#SPJ4

5 0
2 years ago
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