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zaharov [31]
3 years ago
10

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
PolarNik [594]3 years ago
6 0

OPTION C is the correct answer.

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A wire is stretched just to its breaking point by a force F . A longer wire made of the same material has the same diameter. The
ICE Princess25 [194]

Answer: No

Explanation:

The force F required is equal to the Force exerted in stretching the first material since conditions are the same

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3 years ago
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A train travels 8.81 m/s in a -51.0° direction.
Amiraneli [1.4K]

The displacement of the train after 2.23 seconds is 25.4 m.

<h3>Resultant velocity of the train</h3>

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

  • θ is the angle between the velocity = (90 - 51) + 37 = 76⁰

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

<h3>Displacement of the train</h3>

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

Learn more about displacement here: brainly.com/question/2109763

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8 0
2 years ago
What are valence electrons?
SashulF [63]

Answer:

The correct answer is D. Electrons in an atom that can bond with other atoms.

Explanation:

For those of you that need it still

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3 years ago
Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
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Answer:

Plss see attached file

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3 years ago
A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 85.0 m/s2
sergey [27]

Answer:

Maximum height attained by the model rocket is 2172.87 m

Explanation:

Given,

  • Initial speed of the model rocket = u = 0
  • acceleration of the model rocket = a\ =\ 85.0 m/s^2
  • time during the acceleration = t = 2.30 s

We have to consider the whole motion into two parts

In first part the rocket is moving with an acceleration of a = 85.0 m/s^2 for the time t = 2.30 s before the fuel abruptly runs out.

Let s_1 be the height attained by the rocket during this time intervel,

s_1\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s_1\ =\ 0\ +\ 0.5\times 85\times 2.30^2\\\Rightarrow s_1\ =\ 224.825\ m

And Final velocity at that point be v

\therefore v\ =\ u\ +\ at\\\Rightarrow v\ =\ 0\ +\ 85.0\times 2.3\\\Rightarrow v\ =\ 195.5\ m/s.

Now, in second part, after reaching the altitude of 224.825 m the fuel abruptly runs out. Therefore rocket is moving upward under the effect of gravitational acceleration,

Let 's_2' be the altitude attained by the rocket to reach at the maximum point after the rocket's fuel runs out,

At that insitant,

  • initial velocity of the rocket = v = 195.5 m/s.
  • a = -g\ =\ -9.81\ m/s^2
  • Final velocity of the rocket at the maximum altitude = v_f\ =\ 0

From the kinematics,

v^2\ =\ u^2\ +\ 2as\\\Rightarrow 0\ =\ u^2\ -\ 2gs_2\\\Rightarrow s_2\ =\ \dfrac{u^2}{2g}\\\Rightarrow s_2\ =\ \dfrac{195.5^2}{2\times 9.81}\\\Rightarrow s_2\ =\ 1948.02\ m

Hence the maximum altitude attained by the rocket from the ground is

s\ =\ s_1\ +\ s_2\ =\ 224.85\ +\ 1948.02\ =\ 2172.87\ m

6 0
3 years ago
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