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2 years ago

Two planes travel at a constant speed. Plane A travels 2,800 miles in 5 hours. Plane B travels 3,885 miles in 7 hours.

Mathematics

2 answers:

kozerog [31]2 years ago

5 0

Answer: First.

Step-by-step explanation:

Let's find the speed of the first airplane:

2800 ÷ 5 = 560 (miles per hour)

Let's find the speed of the second plane:

3885 ÷ 7 = 555 (miles per hour)

Thus, the first plane flies faster than the second.

Verdich [7]2 years ago

3 0

The first plane is faster.

The first plane travels at 560 miles per hour. The comparisons are 2 hours apart. Add 560 2 times to 2800 and you get 3,920 which is greater than 3,885, the original number of MPH for the second plane.

Meaning the first plane is faster.

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Answer:

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Step-by-step explanation:

So we want to make x the subject of the formula:

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First, distribute the left side:

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3 years ago

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Solve the equation. 4(x − 7) − 128 = 9x − 5(x + 6)

vichka [17]

The equation 4(x − 7) − 128 = 9x − 5(x + 6) has no solution

<h3><u>Solution:</u></h3>

Given that 4(x − 7) − 128 = 9x − 5(x + 6)

We have to find the solution for this equation

4(x − 7) − 128 = 9x − 5(x + 6)

Let us use BODMAS rule to perform the sequence of operations

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.

So let us solve for brackets first

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Now move the terms from R.H.S to L.H.S

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