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ahrayia [7]
3 years ago
11

Two planes travel at a constant speed. Plane A travels 2,800 miles in 5 hours. Plane B travels 3,885 miles in 7 hours.

Mathematics
2 answers:
kozerog [31]3 years ago
5 0

Answer: First.

Step-by-step explanation:

Let's find the speed of the first airplane:

2800 ÷ 5 = 560 (miles per hour)

Let's find the speed of the second plane:

3885 ÷ 7 = 555 (miles per hour)

Thus, the first plane flies faster than the second.

Verdich [7]3 years ago
3 0
The first plane is faster.


The first plane travels at 560 miles per hour. The comparisons are 2 hours apart. Add 560 2 times to 2800 and you get 3,920 which is greater than 3,885, the original number of MPH for the second plane.


Meaning the first plane is faster.
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By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

<em>See the image in the attachment for the referred diagram.</em>

<em />

  • The two triangles, triangle AEC and triangle BDC are similar triangles.
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<em>This implies that</em>:

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<em><u>Given:</u></em>

EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

  • Plug in the values

\frac{8.1}{5.4} = \frac{AE}{2.6}

  • Cross multiply

5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06

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AE = \frac{21.06}{5.4} = 3.9 $ cm

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AB = AC - BC

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\frac{6.15}{BC} = \frac{8.1}{5.4}

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AB = AC - BC

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Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

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