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3 years ago

Use the following to answer Sean takes two 250 mg chewable calcium tablets each day,

Mathematics

1 answer:

svlad2 [7]3 years ago

3 0

6. 1,750 mg in a week 7. 1.75 g in a week

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1 , 3 , 6 , 10 , 15

Bas_tet [7]

First difference,

$\Delta_{1} = a_{2} - a_{1} = 3 - 1 = 2 = 1 + 1$

Second difference,

$\Delta_{2} = a_{3} - a_{2} = 6 - 3 = 3 = 2 + 1$

Third difference,

$\Delta_{3} = a_{4} - a_{3} = 10 - 6 = 4 = 3 + 1$

And so on.

Assuming the pattern holds on, we see that

i-th difference,

$\Delta_{i} = a_{i + 1} - a_{i} = i + 1$

$\implies a_{i + 1} = a_{i} + i + 1$

Then, nth term is,

$\implies a_{n} = a_{n - 1} + n$

$= a_{n - 2}+ (n + (n - 1))$

$= a_{n - 3} + (n + (n - 1) +(n - 2))$

$= a_{n - (n - 1)} + \sum \limits^{n - 2}_{k = 0}(n - k)$

$= a_1 + \sum \limits^{n - 2}_{k = 0}n- \sum \limits^{n - 2}_{k = 0}k$

$= a_1 +n(n -2 + 1 )- \frac{1}{2} (n - 2)(n - 1)$

$= a_1 +n(n -1 )- \frac{1}{2} (n - 2)(n - 1)$

$= a_1 +(n -1 )(n- \frac{1}{2} (n - 2))$

$= a_1 + \frac{1}{2} (n -1 )(2n- n + 2)$

$= a_1 + \frac{1}{2} (n -1 )(n + 2)$

$\implies a_{n} = 1 + \frac{1}{2} (n -1 )(n + 2)$

Now, the 21st term in the sequence is,

$\implies a_{21} = 1 + \frac{1}{2} (21 -1 )(21 + 2)$

$= 1 + \frac{1}{2} \times 20 \times 23$

$= 231$

4 0

3 years ago

A stack of $20, $50, and $100 bills was retrieved as part of a police investigation. There were 40 more $50 bills than $100 bill

denis23 [38]

102772876199300bwjjjqgyq5q5ytq55

6 0

2 years ago

Read 2 more answers

Final grades are often computed using weighted averages. For example, Fran's teacher uses the following: homework 10%, quizzes 2

GarryVolchara [31]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
You are right the answer is D below is the solution:

9.2 + 13.6 + 56.7 = 79.5

4 0

3 years ago

Answer this question. please

dimaraw [331]

Answer:

$\boxed{\textsf{ The total surface area of the cuboid is \textbf{62 cm} $\sf ^2$ .}}$

Step-by-step explanation:

Given that the base area of the cuboid is 7cm² . And it's volume is 21cm³ . We need to find its total surface area . Now here we need to find the height . We can find height as ,

Height :-

$\qquad\boxed{\boxed{\sf Height =\dfrac{ Volume}{Area } }}$

$\sf\implies Height =\dfrac{Volume}{Area} \\\\\sf\implies h =\dfrac{ 21cm^3}{7cm^2}\\\\\implies \boxed{ \pink{\frak { Height = 3 cm.}}}$

$\rule{200}2$

Let's find out the Total surface area .

TSA of cuboid :-

$\qquad\boxed{\boxed{\sf TSA_{(cuboid)} =2(lb + bh + hl ) }}$

Put on the respective values :-

$\sf\implies TSA_{(cuboid)}= 2( lb + bh + hl )\\\\\sf\implies TSA_{(cuboid)}= 2( 7cm\times 1cm + 1cm\times 3cm + 3cm \times 7 cm ) \\\\\sf\implies TSA_{(cuboid)}=2 ( 7cm ^2+3cm^2+21cm^2 ) \\\\\sf\implies TSA_{(cuboid)}= 2\times 31cm^2 \\\\\sf\implies \boxed{\pink{\frak{ TSA_{(cuboid)}= 62 cm^2}}}$