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cluponka [151]
3 years ago
15

Use the following to answer Sean takes two 250 mg chewable calcium tablets each day,

Mathematics
1 answer:
svlad2 [7]3 years ago
3 0
6. 1,750 mg in a week 7. 1.75 g in a week
You might be interested in
1 , 3 , 6 , 10 , 15
Bas_tet [7]

First difference,

\Delta_{1} =  a_{2} - a_{1} = 3 - 1 = 2 = 1  + 1

Second difference,

\Delta_{2} =  a_{3} - a_{2} = 6 - 3 = 3 = 2 + 1

Third difference,

\Delta_{3} =  a_{4} - a_{3} = 10 - 6 = 4  = 3 + 1

And so on.

Assuming the pattern holds on, we see that

i-th difference,

\Delta_{i} =  a_{i + 1} - a_{i} = i + 1

\implies a_{i + 1} = a_{i}  +  i +  1

Then, nth term is,

\implies a_{n} = a_{n - 1} + n

= a_{n - 2}+ (n  + (n - 1))

= a_{n - 3} + (n + (n - 1) +(n - 2))

= a_{n - (n - 1)} + \sum \limits^{n - 2}_{k = 0}(n - k)

= a_1 + \sum \limits^{n - 2}_{k = 0}n-  \sum \limits^{n - 2}_{k = 0}k

= a_1 +n(n -2 + 1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +n(n -1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +(n -1 )(n-  \frac{1}{2} (n - 2))

= a_1 + \frac{1}{2} (n -1 )(2n- n  +  2)

= a_1 + \frac{1}{2} (n -1 )(n  +  2)

\implies a_{n} = 1 + \frac{1}{2} (n -1 )(n  +  2)

Now, the 21st term in the sequence is,

\implies a_{21} = 1 + \frac{1}{2} (21 -1 )(21  +  2)

= 1 + \frac{1}{2}  \times 20 \times 23

= 231

4 0
3 years ago
A stack of $20, $50, and $100 bills was retrieved as part of a police investigation. There were 40 more $50 bills than $100 bill
denis23 [38]

102772876199300bwjjjqgyq5q5ytq55

6 0
2 years ago
Read 2 more answers
Final grades are often computed using weighted averages. For example, Fran's teacher uses the following: homework 10%, quizzes 2
GarryVolchara [31]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
You are right the answer is D below is the solution:

<span>9.2 + 13.6 + 56.7 = 79.5</span>

4 0
3 years ago
Answer this question. please​
dimaraw [331]

Answer:

\boxed{\textsf{ The total surface area of the cuboid is \textbf{62 cm} $\sf ^2$  .}}

Step-by-step explanation:

Given that the base area of the cuboid is 7cm² . And it's volume is 21cm³ . We need to find its total surface area . Now here we need to find the height . We can find height as ,

<u>Height</u><u> </u><u>:</u><u>-</u>

\qquad\boxed{\boxed{\sf Height =\dfrac{ Volume}{Area } }}

\sf\implies Height =\dfrac{Volume}{Area} \\\\\sf\implies h =\dfrac{ 21cm^3}{7cm^2}\\\\\implies \boxed{ \pink{\frak { Height = 3 cm.}}}

\rule{200}2

Let's find out the Total surface area .

<u>TSA </u><u>of </u><u>cuboid</u><u> </u><u>:</u><u>-</u><u> </u>

\qquad\boxed{\boxed{\sf TSA_{(cuboid)} =2(lb + bh + hl ) }}

<u>Put </u><u>on</u><u> the</u><u> respective</u><u> values</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies TSA_{(cuboid)}= 2( lb + bh + hl )\\\\\sf\implies TSA_{(cuboid)}= 2( 7cm\times 1cm + 1cm\times 3cm + 3cm \times 7 cm ) \\\\\sf\implies TSA_{(cuboid)}=2 ( 7cm ^2+3cm^2+21cm^2 ) \\\\\sf\implies TSA_{(cuboid)}=  2\times 31cm^2 \\\\\sf\implies \boxed{\pink{\frak{ TSA_{(cuboid)}=  62 cm^2}}}

3 0
3 years ago
Read 2 more answers
A running track in the shape of an oval is shown. The ends of the track form semicircles.
tigry1 [53]

Answer:

Two semi circles would equal one circle.

The perimeter of a circle is PI x diameter.

The diameter of the circle is shown as 56 m

The perimeter of the 2 ends = 56 x 3.14 = 175.84

The length of the inside of the track is given as 130 m, and there are 2 sides so 130 + 130 = 260 m.

Total perimeter = 260 + 175.84 = 435.84 m.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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