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sveta [45]
3 years ago
14

Please do all of them correct and quick I will mark brainliest and 10 points ty pls I’m on a time limit

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

1: 9pi

2. 18

3. 12pi

4. 672

5. 23.94

6. 10 3/4

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A roll of tape has a circumference of 14.8 centimeters. The circumference decreases 2.4 centimeters after you use some of the ta
Lelu [443]

Answer:

7.900 cm

Step-by-step explanation:

The computation of the diameter after using the tape is given below:

Since the circumference is 14.8 cm

And it would be decrease by 2.4 cm

So, the new circumference is

= 14.8 - 2.4

= 12.4 cm

Now the radius is

= 12.4 ÷ π

= 3.95

And, the diameter is

= 3.95 × 2

= 7.900 cm

6 0
3 years ago
I have no idea about this
Artist 52 [7]
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7 0
3 years ago
Complete the square to find the minimum value of the expression 4x2 + 8x + 23.
Tcecarenko [31]
So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19

I'm going to assume the given equation equals zero..

So, If we add subtract 19 from both sides of the equation we get the perfect square.

4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0

for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)

Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.


3 0
3 years ago
Find the arc length of the semicircle. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a d
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

The formula for the length of an arc is s = rФ.

Thus, the arc length of a semicircle is S = rФ/2.

Here the radius is 5 (half the diameter), and so in this case the arc length is

S = (5 units)π/2, or S = (5/2)(3.14) units, or approximately S = 7.85 units

6 0
3 years ago
7
Rus_ich [418]

Answer:

something.....................

7 0
3 years ago
Read 2 more answers
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