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JulijaS [17]
3 years ago
7

PLEASE HELP MEEE !!!!​

Mathematics
2 answers:
WINSTONCH [101]3 years ago
5 0

Answer:

Step-by-step explanation:

Lets find out first the Area of the rectangle building

A=50*100=5000 ft^2

we have 2 circles with the radius of 42 ft, r=21ft

Acircle=3.14*(21)^2=1384.74

Area of 2 circles=2*1384.74=2769.48

What is not covered by the rings is

5,000.00-2769.48=2230.52, rounded is 2231

Choice A

denis23 [38]3 years ago
5 0
Its choice A. as listed in the comment above of this one
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Based on the information from Harper's Index, 37 out of 100 adult Americans who did not attend college believe in extraterrestri
vazorg [7]

Answer: Yes, this indicate the  proportion of adult americans that attended college and believe in extraterrestrials is higher than the proportion that did not attend college.

Step-by-step explanation:

Since we have given that

Hypothesis:

H_0:p_1=p_2\\\\H_a:p_1>p_2

n₁ = 100

x₁ = 37

So, p_1=\dfrac{x_1}{n_1}=\dfrac{37}{100}=0.37

n₂ = 100

x₂ =47

So, p_2=\dfrac{47}{100}=0.47

At 0.01 level of significance, z = 2.33

So, test statistic value would be

z=\dfrac{p_1-p_2}{\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}}\\\\z=\dfrac{0.37-0.47}{\sqrt{\dfrac{0.37\times 0.63}{100}+\dfrac{0.47\times 0.53}{100}}}\\\\z=-1.44

Since, 2.33>-1.44

Hence, we will reject the null hypothesis.

Therefore, Yes, this indicate the  proportion of adult americans that attended college and believe in extraterrestrials is higher than the proportion that did not attend college

4 0
3 years ago
Help me solve this problem please
AlekseyPX

Answer:

It's A.

Step-by-step explanation:

4 x 2.5 = 10

It's the only true statement

5 0
3 years ago
What kind of shift does the graph have? y = -sin (x-1) from y = sin(x)
Mademuasel [1]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\end{array}
\\\\
-------------------\\\\

\bf \bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\left. \qquad  \right. \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad  \right. \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)

now, with that template in mind, let's see

\bf \begin{array}{lllll}
y=&-1sin(&1x&-1)&+0\\
&A&B&C&D
\end{array}
\\\\\\
\textit{horizontal shift of }\cfrac{C}{B}\implies \cfrac{-1}{1}\implies -1
\\\\\\
\textit{A is negative, so is flipped upside-down}
8 0
3 years ago
Solve for x: |x + 2| + 16 = 14 (2 points)
Neporo4naja [7]

Answer:

d is the qnswer.

Step-by-step explanation:

the value of |X+2| can't be negative.

7 0
4 years ago
If it snows ​tomorrow, the probability is 0.5 that John will practice his trumpet. If it does not snow ​tomorrow, there is only
Crazy boy [7]

Answer:

The probability that Justin will practice soccer this evening is 16%.

Step-by-step explanation:

The probability that John will practice soccer is given by the product of the probability that it won't snow and the probability that he'll practice soccer. This is shown below:

practice soccer = (1 - 0.6)*0.4

practice soccer = 0.4*0.4

practice soccer = 0.16

The probability that Justin will practice soccer this evening is 16%,

8 0
3 years ago
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