Which points on this vertical number line best represent the locations of 2.5 and -

Mathematics

1 answer:

mixas84 [53]3 years ago

6 0

Answer:

i think 1h but wait for someone else to answer to

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1.You’ve fallen down a slippery, eighteen-feet deep hole. Each hour, you climb up three feet, and then slip backwards two feet.

lisov135 [29]

Climb up 3 ft per hr and fall down 2 ft per hr

18 = 3h-2h

solve for h

h=18 hr

7 0

4 years ago

in the second half of the game, the Wildcats again scored 18 points. This time, however, we don't know how many total shots were

Kobotan [32]

Lets start with the chain of 3's:

18 = 3 + 3 + 3 + 3 + 3 + 3

But, we know that

3 + 3 = 2 + 2 + 2

Sol, let's replace 3 + 3 by 2 + 2 + 2 one by one.

Hence, the possible ways of combinations are listed below:

18 = 3 + 3 + 3 + 3 + 2 + 2 + 2 (1)

18 = 3 + 3 + 2 + 2 + 2 + 2 + 2 + 2 (2)

Therefore, there are two combinations of 2- and 3- point shots that could total 18 points.

3 0

3 years ago

If there are x teams in a sports league, and all the teams play each other twice, a total of n(x) games are played, where n

EleoNora [17]

1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.

There are in total $C(n, r)= \frac{n!}{r!(n-r)!}$ many ways of doing so.

where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r

2.

C(x, 2) is the total number of pairs out of x objects, that we can form.

so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.

The total number of games is:

n(x)=2*C(x, 2) = $2* \frac{x!}{2!(x-2)!}= \frac{x!}{(x-2)!}= \frac{x(x-1)(x-2)!}{(x-2)!}=x(x-1)= x^{2} -x$

Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.

Answer: $x^{2} -x$

6 0

3 years ago

A pair of parallel lines is cut by a transversal, as shown below: A pair of parallel lines is cut by a transversal. The interior

DiKsa [7]

See the picture attached to better understand the problem

we know that
(x+20)+∠1=180°-------> by supplementary angles
∠1=160°-x

∠1+∠2=180°--------> by supplementary angles
∠2=180-(160-x)-----> ∠2=20+x

∠2=80°------> by corresponding angles
so
20+x=80
x=80-20-------> x=60°

the answer is
60°