Answer:
0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Sent by ABC Speedy Delivery Service.
Event B: Arrived on time.
The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.
This means that 
The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.
This means that 
Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
This is
. So

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.
Good job oh my God you are so smart oh my God a good job bro
We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:

We can set this equal to 0 and factor by using the quadratic formula which is:

So, let's do just that:

Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:


So, we can write this as:

Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!
Answer:
$55.80
Step-by-step explanation:
8, 16, 24, 32, 36
8=12.40, 16=24.80, 24=37.2, 32=49.6,
+4 makes it 36 so it's have of 8, so add 6.20 to the end and it's 55.80