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miv72 [106K]
2 years ago
9

Miss penny inherits £650. She decides to save some of the money and spend the rest. The ratio of saving to spending money is 9:4

Mathematics
2 answers:
wlad13 [49]2 years ago
7 0

The amount she saves is  £450 and the amount she spends is £200.

Step-by-step explanation:

Given,

The amount she has = £650

The ratio of saving to spending money is 9:4

To find the amount she saves and she spends.

Let,

The amount she saves = 9x

The amount she spends = 4x

According to the problem,

9x+4x = 650

or, 13x = 650

or, x = \frac{650}{13} = 50

Hence,

The amount she saves =  £50×9 =  £450

The amount she spends = £50×4 = £200

blsea [12.9K]2 years ago
3 0

Answer:

Saving=£450

Spent=£200

Step-by-step explanation:

Ratio of saving to spending is 9:4

She inherits £650

So to determine her saving

It will be

9+4=13

Since her saving is 9

So, 9/13 × 650

5850/13

=450

So her saving is£450

To determine what she spent

4/13 × 650

2600/13

200

Saving=£450

Spent=£200

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Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

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The p value for this case taking in count the alternative hypothesis would be:

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Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

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