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son4ous [18]
3 years ago
13

Which is equivalent to7^(3/2) over 7^(1/2)?

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0

Given the expression below:

\large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } }

Use the following property:

\large \boxed{ {a}^{ \frac{m}{n} }  =  \sqrt[n]{ {a}^{m} } }

Therefore:

\large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } =  \frac{  \sqrt{ {7}^{3} }  }{ \sqrt{7} }  }  \\  \large{ \frac{ \sqrt{ {7}^{3} } }{ \sqrt{7} } =  \frac{ \sqrt{7 \times 7 \times 7} }{ \sqrt{7} }   \longrightarrow  \frac{7 \sqrt{7} }{ \sqrt{7} } }  \\  \large{ \frac{7 \cancel{ \sqrt{7} }}{  \cancel{ \sqrt{7} }}  = 7}

Note that a¹ = a. Therefore, 7¹ = 7.

Answer

  • 7¹ or 7.

Doss [256]3 years ago
6 0
The answer is c! you just subtract: 3/2-1/2, which is 1.
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