50 POINTS

Given the graph of a function below, which of the following points would be on the graph of the inverse of the function?

pshichka [43]

Its the second one. The inverse is the opposite of the original

4 0

3 years ago

Joe worked at Walmart for 40 hours at his regular pay of $13.50/hr. He also worked for 8 hours at his overtime wage of time and

kotykmax [81]

Joe has earned $702 in total

To work through this problem, we can first calculate how much money Joe earned at regular pay:
40 (number of hours) x 13.5 (pay rate) = 540 (in dollars)

Now, before we figure out how much he earned working overtime, we must calculate his overtime pay rate (time and a half). We do this by multiplying his normal pay rate by 1.5:
13.5 x 1.5 = 20.25 ($/hr.)

Now we can calculate his overtime total:
8 (number of hours) x 20.25 (overtime pay rate) = 162 (in dollars)

So, to find the total amount of money Joe earned, we have to add the two totals together:

540 + 162 = 702

Thus, Joe has earned $702 in total

Hope this helped!

4 0

3 years ago

Calculate the vapor pressure (in torr) of a solution containing 0.2 moles of solute dissolved in 10 moles of water at 25°C. Vapo

Gnesinka [82]

Answer:

the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (180.2 g/mole) in 250.0 mL of water. The vapor pressure of pure water at 25°C

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Ans this sum plsss .

FrozenT [24]

Answer:

See below ↓

Step-by-step explanation:

3.

2/5
12/25
3/7
3/8
3/10

4.

Draw a number of spacing 0.25 each
Start from -1 to 1
-2/8 = -0.25 [mark on line]
3/6 = 0.5 [mark on line]

5.

Midpoint of -2/5 and 1/2
M = [-2/5 + 1/2] / 2
M = [1/10] / 2
M = 1/20

8 0

2 years ago

Tensile-strength tests were carried out on two different grades of wire rod (Fluidized Bed Patenting of Wire Rods, Wire J., June

Shtirlitz [24]

Answer:

$t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569$

$p_v =P(t_{256}>28.569) \approx 0$

So with the p value obtained and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.

Step-by-step explanation:

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2 +10$

Alternative hypothesis: $\mu_1 >\mu_2 +10$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 \leq 10$

Alternative hypothesis: $\mu_1 -\mu_2>10$

Our notation on this case :

$n_1 =129$ represent the sample size for group AISI 1078

$n_2 =129$ represent the sample size for group AISI 1064

$\bar X_1 =123.6$ represent the sample mean for the group AISI 1078

$\bar X_2 =107.6$ represent the sample mean for the group AISI 1064

$s_1=2.0$ represent the sample standard deviation for group 1 AISI 1078

$s_2=1.3$ represent the sample standard deviation for group AISI 1064

And now we can calculate the statistic:

$t=\frac{(123.6-107.6)-(10)}{\sqrt{\frac{2^2}{129}+\frac{1.3^2}{129}}}=28.569$

Now we can calculate the degrees of freedom given by:

$df=129+129-2=256$

And now we can calculate the p value using the altenative hypothesis:

$p_v =P(t_{256}>28.569) \approx 0$

So with the p value obtained and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true average strength for the 1078 grade exceeds that for the 1064 grade by more than 10 kg/mm2.

7 0

3 years ago