Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD = 
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
= 
= 
= 0.6
Step-by-step explanation:
As it can't be expressed in the form p/q, where q is not equal to 0,
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>square</u></em><em><u> </u></em><em><u>root</u></em><em><u> </u></em><em><u>65</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>an</u></em><em><u> </u></em><em><u>irrational</u></em><em><u> </u></em>
Answer:
0.8
Step-by-step explanation:
P(AP statistics) = 65%
P(AP Calculus) = 45%
P(AP statistics n AP Calculus) = 30%
Probability of AP statistics or AP Calculus but not both :
Probability of event A or B :
P(AUB) = p(A) + p(B) - p(AnB)
P(AP statistics U AP Calculus) = P(AP statistics) + P(AP Calculus) - P(AP statistics n AP Calculus)
= 0.65 + 0.45 - 0.30
= 0.8
= 80%
Answer:
109,420,982
Step-by-step explanation:
9514 1404 393
Answer:
D. y = ±√(25 -x²)
Step-by-step explanation:
Subtract x² and take the square root to solve for y.
x² +y² = 25 . . . . . . . given
y² = 25 -x² . . . . . . . . subtract x²
y = ±√(25 -x²) . . . . . take the square root
