Answer:

Step-by-step explanation:
Consider the selling of the units positive earning and the purchasing of the units negative earning.
<h3>Case-1:</h3>
- Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
- Mr.A earns Rs6000
So, the equation would be

<h3>Case-2:</h3>
- Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
- Mr B neither lose nor gain meaning he has made 0₹
hence,

<h3>Case-3:</h3>
- Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
- Mr.C earns 13000₹
therefore,

Thus our system of equations is

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>
we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

Now solve the equation accordingly:

Solving the equation for x and y yields:

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437
Year 1: 7lbs x 3years= 21lbs
Year 2: 21lbs x 3years = 63lbs
Answer:
£44
Step-by-step explanation:
We have been given the ratio 1 : 3 , where 1 is stephens value and 3 is bridgets value.
We have told that stephen gets £11.
The relationship between stephens 'value' of 1 and the amount of money that he actually gets (11) is x11.
Therefore we must also x11 to Bridgets value.
11 x 3 = £33
Now, we add the two answers to find how much they won in total.
£33 + £11 = £44
hope this helps :)
Answer:
The system has an infinite solution at k = 6, otherwise for any value of k, it has zero solution.
Step-by-step explanation:
Consider the system of linear equations:

The system of linear equations can have zero, one, or an infinite number of solutions:
simplify equation (1):

substitute in equation (2), we get

we cannot find the value of
and
.
so, there is no solution.
Multiply the equation (1) with 3 and put k is 6,

it means both equations are overlapped. Then, the solution has infinite solutions.
Hence, the system has an infinite solutions at k is 6 otherwise for any value of k it has no solution.