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Hoochie [10]
3 years ago
6

What are the domain and range of the logarithmic function f(x) = log7x?

Mathematics
1 answer:
kap26 [50]3 years ago
6 0
The domain is (0, ∞)
The range is (-∞, ∞)
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8 cups lemon juice
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3 years ago
Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by p = 130e0.0205t,wh
svetoff [14.1K]

Answer: a) 236,000.

b) 2021

Step-by-step explanation:

Given : Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by p = 130e^{0.0205t}    (1)

where t = 0 corresponds to 1980.

Then , for 2009

t= 2009-1980=29

a. ⇒The population of Phoenix in 2009 =  p = 130e^{0.0205(29)}

p = 130e^{0.5945}

p =130(1.81212465608)=235.57620529\approx236

Hence, the population of Orlando in 2009 was about 236,000.

b) Substitute p= 300 in (1) , we get

300 = 130e^{0.0205t}

2.3077= e^{0.0205t} (Divide both sides by 130)

Taking Natural log on both sides,

\ln(2.3077) = 0.0205t\\\\\Rightarrow\ t=\dfrac{\ln(2.3077)}{0.0205}

t=\dfrac{0.836251357528}{0.0205}=40.7927491477\approx41

Hence, The year Orlando will have a population of 300,000 =1980+41 =2021

6 0
3 years ago
I need help on my quiz!
Fantom [35]
I can’t see good this image
3 0
3 years ago
Equation y=0.25x+10 explain in words what each letter and number on your equation means
enot [183]
The 0.25 is the rate of change per each time. the 10 is what it started it
8 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
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